这实际上是my earlier question today的导数.
我在数据库中创建了一个存储过程,希望从PHP连续调用多次.
假设这是我的程序:
CREATE PROCEDURE PROC_1(
IN param1 VARCHAR(255),
IN param2 VARCHAR(255))
BEGIN
DECLARE ok INT;
DECLARE success, failure VARCHAR(255);
/* several SELECT, IF ... THEN, INSERT and UPDATE operations which then SET ok var to 0 or 1 */
IF ok = 1 THEN
SET success = 'Everything went well';
SELECT success;
LEAVE;
ELSE
SET failure = 'Problem description';
SELECT failure;
LEAVE;
END IF;
END
我这样做(短版):
$calls = array(
"CALL PROC_1('param1', 'param2')",
"CALL PROC_1('param3', 'param4')",
"CALL PROC_1('param5', 'param6')",
);
// assuming I'm already connected to DB with $link
foreach ($calls as $i => $call)
{
echo $i . ': ';
$result = MysqL_query($call);
$ok = ($result === FALSE) ? FALSE : TRUE;
var_dump($ok);
if ($result !== FALSE)
MysqL_free_result($result);
}
第一次迭代按预期工作,但是返回FALSE之后的任何事情.
这是为什么?
0: bool(true)
1: bool(false)
2: bool(false)
有趣的是,我检查了MysqL日志(设置为记录所有查询的日志记录),并且只有第一个查询到达了服务器.下一个查询永远不会到达服务器.
PS.我正在运行PHP 5.3.2和Apache 2.2.17.
UPDATE
根据Shakti Singh的建议,在查询数据库之前,我已经检查了$link状态.我注意到自第二次迭代以来存在错误,因此这是带有错误的输出:
ERROR: (0)
0: bool(true)
ERROR: (0)
ERROR: (0)
1: bool(false)
ERROR: (2014) Commands out of sync; you can't run this command Now
ERROR: (2014) Commands out of sync; you can't run this command Now
2: bool(false)
ERROR: (2014) Commands out of sync; you can't run this command Now
101126 15:46:28 [Warning] Aborted connection 129 to db: 'db1' user: 'root' host: 'localhost' (Got an error reading communication packets)
解决方法:
在PHP中,当我们在循环中调用存储过程时,它只需执行一次即可.当存储过程返回任何结果集时,就会发生这种情况.
我遇到了同样的问题.我有一个用于更新表记录的存储过程.
DELIMITER $$
DROP PROCEDURE IF EXISTS `espritkm`.`update_notification`$$
CREATE DEFINER=`root`@`localhost` PROCEDURE `update_notification`(item_id_val VARCHAR(11),item_source_val VARCHAR(50),item_type_id_val INT(50),item_type_val VARCHAR(50),created_at_val BIGINT(11),pivot_user_id_val VARCHAR(256),pivot_item_type_val VARCHAR(64),pivot_owner_type_val VARCHAR(64),pivot_owner_id_val INT(11),user_id_val VARCHAR(64), OUT row_effect VARCHAR(11))
Begin
Declare item_count INT(10);
SET @sql1 = CONCAT('select count(*) into @item_count from item_notifications where item_id = ''', item_id_val, ''''); PREPARE S1 FROM @sql1; EXECUTE S1; DEALLOCATE PREPARE S1;
IF @item_count = 0 THEN
SET @sql2 = CONCAT('INSERT INTO item_notifications (item_id,item_source,item_type_id,item_type,created_at,pivot_user_id,pivot_item_type,pivot_owner_type,pivot_owner_id,user_id) value(''',item_id_val,''',''',item_source_val,''',''',item_type_id_val,''',''',item_type_val,''',''',created_at_val,''',''',pivot_user_id_val,''',''',pivot_item_type_val,''',''',pivot_owner_type_val,''',''',pivot_owner_id_val,''',''',user_id_val,''')');
PREPARE S2 FROM @sql2; EXECUTE S2; DEALLOCATE PREPARE S2;
SET row_effect= "Insert";
ELSE
SET row_effect= "Update";
SET @sql3 = CONCAT('UPDATE item_notifications SET viewer_id = ''',user_id_val,''' WHERE item_id = ''' ,item_id_val,'''') ;
PREPARE S3 FROM @sql3; EXECUTE S3; DEALLOCATE PREPARE S3;
END IF;
SELECT row_effect;
END$$
DELIMITER ;
并且本应执行1000行,但仅执行一条记录.
当您的SP返回任何数据集时,它不支持.只需消除OUT var或任何select语句(仅用于任何结果引用),它就可以正常工作.