PHP 1-liner each()与mysql_fetch_assoc()

尝试创建1-liner以遍历mysql结果集.

例：

$sql = "SELECT uid, role FROM usr WHERE uid = '$this->uid'";
$r = db::q($sql);
if($r->rows()) {
  $q = MysqL_fetch_assoc($r->result);
  while(list($k, $v) = each($q)) { // would like to omit line above and consolidate here
    $_SESSION['usr'][$k] = $this->$k = $v;
  }
}

问题是像这样合并while循环：

while(list($k, $v) = each(MysqL_fetch_assoc($r->result))

返回错误la each()不会获取对象或数组,即使它确实是.我认为该问题是强制性问题,但是您似乎无法做到：

each( (array) MysqL_fetch_assoc($r->result))

有任何想法吗？我喜欢尽可能简洁地编写代码,并且到处都有“ $q = MysqL_fetch_assoc($r-> result)”会惹恼我.

保持更新…

谢谢！

解决方法:

$_SESSION['usr'] = MysqL_fetch_assoc($r->result);

或(如果$_SESSION [‘usr’]已包含某些元素以及要保留的其他键)

$_SESSION['usr'] = array_merge($_SESSION['usr'], MysqL_fetch_assoc($r->result));