考虑这个表some_table:
+--------+----------+---------------------+-------+ | id | other_id | date_value | value | +--------+----------+---------------------+-------+ | 1 | 1 | 2011-04-20 21:03:05 | 104 | | 2 | 1 | 2011-04-20 21:03:04 | 229 | | 3 | 3 | 2011-04-20 21:03:03 | 130 | | 4 | 1 | 2011-04-20 21:02:09 | 97 | | 5 | 2 | 2011-04-20 21:02:08 | 65 | | 6 | 3 | 2011-04-20 21:02:07 | 101 | | ... | ... | ... | ... | +--------+----------+---------------------+-------+
我想通过other_id选择和分组,以便我只获得唯一的other_ids.此查询有效(信用@MichaelPakhantsov):
select id,other_id,date_value,value from ( SELECT id,value,ROW_NUMBER() OVER (partition by other_id order BY Date_Value desc) r FROM some_table ) where r = 1
如何为每个other_id获得相同的结果,但是计算了分组的行数.期望的结果如下:
+--------+----------+---------------------+-------+-------+ | id | other_id | date_value | value | count | +--------+----------+---------------------+-------+-------+ | 1 | 1 | 2011-04-20 21:03:05 | 104 | 3 | | 5 | 2 | 2011-04-20 21:02:08 | 65 | 2 | | 3 | 3 | 2011-04-20 21:03:03 | 130 | 2 | +--------+----------+---------------------+-------+-------+
我已尝试在内部和外部选择中使用COUNT(other_id),但它会产生此错误:
ORA-00937: not a single-group group function
注意:类似于this question(示例表和从那里获取的答案),但该问题没有给出折叠行的计数.