Node.js：指定要使用zlib tar解压缩的文件

安装过程正在下载.tar.gz存档,然后将文件解压缩到目标目录.但是,并非所有文件都是必需的,我想指定应提取哪些文件.天真的方法是在提取后删除不必要的文件,但我想要一种“更清洁”的方式并过滤掉.

这可能吗？

到目前为止我的(相关)代码(为了便于阅读而被剥离)

var fs = require('fs');
var tar = require('tar');
var zlib = require('zlib');

var log = console.log;

var tarball = 'path/to/downloaded/archive.tar.gz';
var dest = 'path/to/destination';

fs.createReadStream(tarball)
  .on("error",log)
  .pipe(zlib.Unzip())
  .pipe(tar.Extract({ path: dest }))
  .on("end",log);

谢谢.

解决方法

它的工作原理类似于 unzip模块：

var fs = require('fs');
var tar = require('tar');
var zlib = require('zlib');
var path = require('path');
var mkdirp = require('mkdirp'); // used to create directory tree

var log = console.log;

var tarball = 'path/to/downloaded/archive.tar.gz';
var dest    = 'path/to/destination';

fs.createReadStream(tarball)
  .on('error',log)
  .pipe(zlib.Unzip())
  .pipe(tar.Parse())
  .on('entry',function(entry) {
    if (/\.js$/.test(entry.path)) { // only extract JS files,for instance
      var isDir     = 'Directory' === entry.type;
      var fullpath  = path.join(dest,entry.path);
      var directory = isDir ? fullpath : path.dirname(fullpath);

      mkdirp(directory,function(err) {
        if (err) throw err;
        if (! isDir) { // should really make this an `if (isFile)` check...
          entry.pipe(fs.createWriteStream(fullpath));
        }
      });
    }
  });