Sqlserver in 实现 参数化查询 XML类型解决方案

1：如果参数是int类型：

declare @a xml
set @a='
<row><id>1</id></row>
<row><id>5</id></row>
<row><id>4</id></row>
<row><id>3</id></row>
<row><id>2</id></row>'
select * from product where id in (
select d.x.value('./id[1]','int') from @a.nodes('/*') as d(x))

 

2：如果参数是varchar类型：

declare @a xml
set @a='
<row><name>a</name></row>
<row><name>b5</name></row>
<row><name>c4</name></row>
<row><name>d3</name></row>
<row><name>e2</name></row>'
select * from product where pname in (
select d.x.value('./name[1]','varchar(100)') from @a.nodes('/*') as d(x))

 

以第一个为例写的C#简单方法

    public DataSet GetData(List<int> idList) {
        System.Text.StringBuilder idXML = new System.Text.StringBuilder();
        // 把IdList转换成idxml（后面要用到的xml参数的值）
        foreach (var item in idList)
        {
            idXML.AppendFormat("<row><id>{0}</id></row>",item);
        }

        System.Text.StringBuilder strsql = new System.Text.StringBuilder();
        strsql.Append("select * from product where id in (");
        // 解析xml参数@a 取出ID 这里可以认为@a是一个特殊的表
        strsql.Append("select d.x.value('./id[1]','int') from @a.nodes('/*') as d(x)");

        strsql.Append(")");
        sqlConnection con = new sqlConnection("数据库连接字符串");
        sqlCommand cmd = new sqlCommand(strsql.ToString(),con);
        // 参数赋值
        sqlParameter[] para = new sqlParameter[]{
            new sqlParameter("@a",sqlDbType.Xml){Value= idXML.ToString()}
        };
        cmd.Parameters = para;

        // 查询
        sqlDataAdapter sda = new sqlDataAdapter(cmd);
        DataSet ds = new DataSet();
        sda.Fill(ds);
        return ds;
    }

来源：http://www.cnblogs.com/tangruixin/archive/2012/04/23/2465917.html