我有一个程序调用另一个程序.他们从不回复对方或打电话给自己,但我收到错误回复,表明他们是.程序如下:
CREATE PROCEDURE grantPermission (perm VARCHAR(30), target VARCHAR(30), id VARCHAR(8), host VARCHAR(45), passwd VARCHAR(45))
BEGIN
SET @setPermissionCmd = CONCAT('GRANT ', perm, ' ON ', target, ' TO ''', id, '''@''', host, ''' IDENTIFIED BY ''', passwd, ''';');
PREPARE setPermissionStmt FROM @setPermissionCmd;
EXECUTE setPermissionStmt;
DEALLOCATE PREPARE setPermissionStmt;
FLUSH PRIVILEGES;
END
和
CREATE PROCEDURE grantAdmin (id VARCHAR(8), host VARCHAR(45), passwd VARCHAR(45))
BEGIN
CALL grantPermission('EXECUTE', 'PROCEDURE createuser', id, host, passwd);
CALL grantPermission('EXECUTE', 'PROCEDURE grantAdmin', id, host, passwd);
CALL grantPermission('EXECUTE', 'PROCEDURE revokeAdmin', id, host, passwd);
CALL grantPermission('INSERT,UPDATE', 'TaskType', id, host, passwd);
CALL grantPermission('UPDATE', 'User', id, host, passwd);
UPDATE User SET isAdmin=1 WHERE dbUser=id;
FLUSH PRIVILEGES;
END
当我调用第二个程序时,我收到以下响应:
MariaDB [pattsdb]> CALL grantAdmin('patts', '%', 'patts');
ERROR 1456 (HY000): Recursive limit 0 (as set by the max_sp_recursion_depth variable) was exceeded for routine grantAdmin
为什么它认为我的程序是递归的?只是因为定义文本中提到了这个名字?
解决方法:
将其添加到存储过程的开头:
SET max_sp_recursion_depth=255;