Lua unpack()搞乱参数

我有这个测试功能,它只是打印传递给它的值
function test1(...)
  for k,v in ipairs(arg) do
    print(v)    
  end
end

function test2(...)
  for k,v in pairs(arg) do
    print(v)    
  end
end

-- GOOD behavior
test1(1,2,3,4) -- produces 1 2 3 4
test2(1,4) -- produces 1 2 3 4

-- BAD behavior
test1( unpack({1,2}),4) -- produces 1 3 4
test2( unpack({1,4) -- produces 1 3 4 3

有人可以向我解释这种行为吗?

解决方法

此行为不是特定于解压缩.
Lua Reference Manual说:

“Both function calls and vararg expressions can result in multiple values. If a function call is used as a statement (see §3.3.6),then its return list is adjusted to zero elements,thus discarding all returned values. If an expression is used as the last (or the only) element of a list of expressions,then no adjustment is made (unless the expression is enclosed in parentheses). In all other contexts,Lua adjusts the result list to one element,either discarding all values except the first one or adding a single nil if there are no values.

(我的重点)

相关文章

1.github代码实践源代码是lua脚本语言,下载th之后运行thmai...
此文为搬运帖,原帖地址https://www.cnblogs.com/zwywilliam/...
Rime输入法通过定义lua文件,可以实现获取当前时间日期的功能...
localfunctiongenerate_action(params)localscale_action=cc...
2022年1月11日13:57:45 官方:https://opm.openresty.org/官...
在Lua中的table(表),就像c#中的HashMap(哈希表),key和...