linux – monit从启动程序命令中删除引号

我正在调试monit启动/停止程序语句.在我的/etc/monit.conf文件中,我的启动程序语句如下所示：

check process node with pidfile /home/ec2-user/blah/node.pid
    start program = "/bin/su -c 'export APP_ENV=development; /home/ec2-user/local/bin/node /home/ec2-user/example.com/current/api.js start &> /tmp/monit.out ' "
    stop program = "/bin/su -c '/home/ec2-user/local/bin/node /home/ec2-user/example.com/current/api.js stop'""

我在shell中测试过

$sudo su
# env -i PATH=/bin:/usr/bin:/sbin:/usr/sbin /bin/sh
# /bin/su -c '/usr/bin/env APP_ENV=development; /home/ec2-user/local/bin/node /home/ec2-user/example.com/current/api.js start &> /tmp/monit.out '

运行它会在/tmp/monit.out文件中返回正确的输出：

Starting nodejs daemon...
nodejs daemon started. PID: 16408

但是当我运行sudo monit -v monitor节点时,它会显示一个不同的命令,除了内部单引号被删除之外：

The service list contains the following entries:

Process Name          = node
 Pid file             = /home/ec2-user/blah/node.pid
 Monitoring mode      = active
 Start program        = '/bin/su -c export APP_ENV=development; /home/ec2-user/local/bin/node /home/ec2-user/example.com/current/api.js start &> /tmp/monit.out ' timeout 30 second(s)
 Stop program         = '/bin/su -c /home/ec2-user/local/bin/node /home/ec2-user/example.com/current/api.js stop' timeout 30 second(s)
 Existence            = if does not exist 1 times within 1 cycle(s) then restart else if succeeded 1 times within 1 cycle(s) then alert
 Pid                  = if changed 1 times within 1 cycle(s) then alert
 Ppid                 = if changed 1 times within 1 cycle(s) then alert

System Name           = system_ip-xx-xx-xx-xx.ec2.internal
 Monitoring mode      = active

我在monit文档中找不到任何相关内容.文档here似乎是最终的参考,但没有通过源代码,我不知道下一步该怎么做.

我的命令工作完美,没有删除引号,所以我只需要解决这个问题.欢迎所有想法和可能的修复.

最佳答案

这是一个相当晚的答案,但我觉得它很重要,因为它会引起一些误解(所以我误导了)

您不需要转义单引号字符.试试吧：

check process fake_proc
  with pidfile /tmp/test_pid
  start = "/bin/bash -c 'echo $$> /tmp/test_pid'"
  stop = "echo stop > /tmp/test_pid"

它不会显示为已启动的进程,但会创建test_pid文件.添加;睡眠xx以捕获进程并检查其属性.

问题可能是由某个特定环境问题引起的.