ORG.json处理

//使用new JSONObject()构造一个JSON对象，参数为空

public String jsontest() throws JSONException{

JSONObject json= new JSONObject();

JSONArray jsonMembers = JSONArray();

JSONObject member1 = JSONObject();

member1.put( "loginname" , "jack" );

"password" "userpass" );

"email" "[e-mail]" );

"sign_date" "2007-06-12" );

jsonMembers.put(member1);

JSONObject member2 = JSONObject();

member2.put( "tom" );

);

"[e-mail]" );

"2008-07-16" );

jsonMembers.put(member2);

json.put( "users" //以字符串形式返回JSON对象的内容

return json.toString();

}

//从字符串构造一个JSON对象并解析之

String jsonTest2() JSONException{

String jsonString= "{\"users\":[{\"loginname\":\"jack\",\"password\":\"userpass\",\"email\":\"[e-mail]\"},{\"loginname\":\"tom\",\"email\":\"[e-mail]\"}]}" ;

JSONObject json= JSONObject(jsonString);

JSONArray jsonArray=json.getJSONArray( );

String loginNames= "loginname list:" ;

for ( int i= 0 ;i<jsonArray.length();i++){

JSONObject user=(JSONObject) jsonArray.get(i);

String userName=(String) user.get( );

if (i==jsonArray.length()- 1 ){

loginNames+=userName;

} else {

loginNames+=userName+ "," ;

}

}

loginNames;

}