简单的工作json.net的例子在VB.net

我有一个提供者以下简化的 JSON字符串,自从我使用Visual Studio和vb.Net以来已经很久了,所以我很生锈！

{
"Venue": {
    "ID": 3145,"Name": "Big Venue,Clapton","NameWithTown": "Big Venue,Clapton,London","NameWithDestination": "Big Venue,"ListingType": "A","Address": {
        "Address1": "Clapton Raod","Address2": "","Town": "Clapton","County": "Greater London","Postcode": "PO1 1ST","Country": "United Kingdom","Region": "Europe"
    },"ResponseStatus": {
        "ErrorCode": "200","Message": "OK"
    }
}
}

我想使用JSON.Net将其转换为我可以使用的东西,我已经阅读了示例等,JSON.net看起来像答案,但我没有在哪里.

我的.Net代码(Me.TextBox1.Text包含上面显示的JSON)

Imports Newtonsoft.Json

Public Class Form1

Private Sub Button1_Click(sender As Object,e As EventArgs) Handles Button1.Click
    Dim obj As JSON_result
    obj = JsonConvert.DeserializeObject(Of JSON_result)(Me.TextBox1.Text)

    MsgBox(obj.ID)
End Sub
End Class

Public Class JSON_result
    Public ID As Integer
    Public Name As String
    Public NameWithTown As String
    Public NameWithDestination As String
    Public ListingType As String
 End Class

有人可以解释为什么obj.ID总是以0的形式出现,为什么我的类的其他属性都没有被填充,我需要做什么来解决这个问题,没有报错.

您的类JSON_result与您的JSON字符串不匹配.请注意,JSON_result对象将如何包含在另一个名为“Venue”的属性中.

所以要创建一个类,例如：

Public Class Container
    Public Venue As JSON_result
End Class

Public Class JSON_result
    Public ID As Integer
    Public Name As String
    Public NameWithTown As String
    Public NameWithDestination As String
    Public ListingType As String
End Class

Dim obj = JsonConvert.DeserializeObject(Of Container)(...your_json...)

或将JSON字符串更改为

{
    "ID": 3145,"Message": "OK"
    }
}

或使用例如一个ContractResolver来解析JSON字符串.