我有一个数组:
var arr = [ {price: 5,amount: 100},{price: 3,amount: 50},{price: 10,amount: 20},amount: 75},{price: 7,amount: 15},amount: 65},{price: 2,amount: 34} ]
我想删除具有相同价格的重复项,并且仅保留最后一个重复项,然后根据价格从最高到最低对数组进行排序.这是我想要的结果:
var result = [ {price: 10,{price : 7,{price: 5,amount: 34} ]
解决方法
使用reduce将对象首先转换为删除重复项,最后一个副本应覆盖前一个对象
var obj = arr.reduce( ( acc,c ) => Object.assign(acc,{[c.price]:c.amount}),{});
将其转换回数组并对其进行排序
var output = Object.keys( obj ) .map( s => ({ price : s,amount : obj[ s ] }) ) .sort( ( a,b ) => b.price - a.price );
演示
var arr = [ {price: 5,amount: 34} ]; var obj = arr.reduce( ( acc,{}); var output = Object.keys( obj ) .map( s => ({ price : s,b ) => b.price - a.price ); console.log( output );