javascript – 从ExtJS 4中的定制模型类扩展

如何从extjs中的定制模型扩展.

有没有什么方法可以直接参与用户和企业用户字段的领域,当我将在下面的例子中引用BusinessUser类的字段.

Ext.define('User',{
    extend: 'Ext.data.Model',fields: [
        {name: 'name',type: 'string'},{name: 'age',type: 'int'},{name: 'phone',{name: 'alive',type: 'boolean',defaultValue: true}
    ],});

Ext.define('BusinessUser',{
    extend: 'User',fields: [
        {name: 'businessType',{name: 'company',type: 'string'}
    ],});

解决方法

您不需要手动加入这些字段,因为它自动完成.根据您的问题检查代码中的输出：

Ext.define('User',});

// instantiating a User object
var u = Ext.create('BusinessUser',{
    name: 'John Doe',age: 30,phone: '555-5555'
});

// instantiating a BusinessUser object
var bu = Ext.create('BusinessUser',{
    name: 'Jane Doe',age: 40,phone: '555-5556',businessType: 'analyst',company: 'Acme'
});

console.log(Ext.getClassName(bu)); // "BusinessUser"
console.log(Ext.getClassName(u));  // "User"
console.log(u  instanceof User); // true
console.log(bu instanceof User); // true
console.log(u  instanceof BusinessUser); // false
console.log(bu instanceof BusinessUser); // true
console.log(u  instanceof Ext.data.Model); // true
console.log(bu instanceof Ext.data.Model); // true
console.log(u  instanceof Ext.data.Store); // false,just to check if it's not returning true for anything
console.log(bu instanceof Ext.data.Store); // false
console.log("name"    in u.data);  // true
console.log("name"    in bu.data); // true
console.log("company" in u.data);  // false
console.log("company" in bu.data); // true