我有一个DIV列表,像这样:
<div id="list"> <div class="cat1-4.2"><div>4</div></div> <div class="cat3-3.3"><div>3</div></div> <div class="cat2-5.1"><div>5</div></div> <div class="cat3-1.5"><div>1</div></div> <div class="cat3-2.4"><div>2</div></div> </div>
我想用jQuery对它们进行排序
在服务器端,我可以定义所需的订单,并在类名中包含此订单:
CATX-4.2
我想能够调用第一个订单(在我的例子中,这个DIV将在第4个位置),或者第二个订单(它将在第2个位置):这解释了“4.2”
所以,如果我打电话给OrderDIV(1),我会这样:
1 2 3 4 5
如果我打电话给OrderDIV(2)我会这样:
5 4 3 2 1
(我需要添加更多订单,例如:catX-4.2.5.6.2)
非常感谢您的帮助!
解决方法
你在中途改变了要求……就像真正的客户一样.更新版本附带一些注释.只是为了确认,前面有两个“可配置”变量.
classprefix:用于确定排序顺序的类唯一的“前缀”(在这种情况下为“cat”)
listElementSelector:用于获取要排序的列表的jQuery选择器.
function OrderDIV(position) { var classprefix = 'cat'; var listElementSelector = '#list'; // -- Decrement the position to make it 0 based position--; // -- Parses the "position" section from the given classes,and // then the position at the specific index requested. var parsePosition = function(classes,pos) { // -- Split the "classes" into an array. var classList = classes.split(' '); // -- Determine which of the "classes" starts with the prefix we want. for( var i in classList ) { if( classList[i].substr(0,classprefix.length) == classprefix ) { // -- Strip out the positions section,and split it. var positions = classList[i].split('-')[1].split('.'); // -- return the one position we want return positions[pos]; } } // -- In the event that we don't find the class we're looking for ... return -1; } // -- Compares div A to div B,and returns an indicator of the order var funcSort = function(a,b) { // -- Use "parsePosition" to determine the sortable criteria from the classes. var compA = parsePosition($(a).attr('class'),position); var compB = parsePosition($(b).attr('class'),position); return (compA < compB) ? -1 : (compA > compB) ? 1 : 0; }; // -- Select the list element. var list = $(listElementSelector); // -- Select the list items,and return them as an array. var listitems = list.children('div').get(); // -- Sort the array using the "funcSort". listitems.sort(funcSort); // -- Go through each of the array entries,and "append" them to the list container // (this moves them to the 'back' of the list) $.each(listitems,function(idx,itm) { list.append(itm); }); }