这是我现在正在处理的类似代码:
<div class="gallery-category">
<h2 data-gallery="Exterior">
<span class="gallery-back"></span>
Exterior
</h2>
<div class="gallery-items-wrap">
<div class="gallery-image-tile">
<div class="gallery-img" data-analytics="photo-click">
<picture>
<source srcset="/content/image/image1.jpg">
</picture>
</div>
</div>
</div>
</div>
<div class="gallery-category">
<h2 data-gallery="Interior">
<span class="gallery-back"></span>
Interior
</h2>
<div class="gallery-items-wrap">
<div class="gallery-image-tile">
<div class="gallery-img" data-analytics="photo-click">
<picture>
<source srcset="/content/image/image2.jpg">
</picture>
</div>
</div>
</div>
</div>
如果我点击图片image1.jpg,我必须得到值外观.我创建了数据属性数据库,并试图通过使用$(‘[data-gallery]’).data(“gallery”)来获取值,但只获取第一个值.
我需要的东西看起来像这样:
单击image1获取值“外部”.
单击image2获取值’Interior’.
提前致谢
解决方法:
是的,您可以通过将单击附加到类.gallery-img然后在单击后使用nearest()方法转到parent div并找到具有data-gallery属性的h2元素:
$('.gallery-img picture').on('click',function(){
$(this).closest('.gallery-category').find('h2[data-gallery]').data("gallery")
})
希望这可以帮助.
$('.gallery-img picture').on('click',function(){
var gallery_data = $(this).closest('.gallery-category').find('h2[data-gallery]').data("gallery");
console.log(gallery_data);
})
picture {
width: 100px;
height: 20px;
border: 1px solid;
display: block;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="gallery-category">
<h2 data-gallery="Exterior">
<span class="gallery-back"></span>
Exterior
</h2>
<div class="gallery-items-wrap">
<div class="gallery-image-tile">
<div class="gallery-img" data-analytics="photo-click">
<picture>
<source srcset="/content/image/image1.jpg">
</picture>
</div>
</div>
</div>
</div>
<div class="gallery-category">
<h2 data-gallery="Interior">
<span class="gallery-back"></span>
Interior
</h2>
<div class="gallery-items-wrap">
<div class="gallery-image-tile">
<div class="gallery-img" data-analytics="photo-click">
<picture>
<source srcset="/content/image/image2.jpg">
</picture>
</div>
</div>
</div>
</div>