如何在没有孩子的情况下获取元素的文本?
element.textContent和element.innerText似乎都不起作用.
HTML:
<body>
<h1>Test heading</h1>
<div>
Awesome video and music. Thumbs way up. love it. Happy weekend to you and your family. love, Sasha
</div>
</body>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
<script type="text/javascript">
fool("body");
</script>
这是傻瓜功能:
jQuery.fn.justtext = function(text) {
return $(this).clone()
.children()
.remove()
.end()
.text();
};
function fool(el) {
reverse(el);
function reverse(el) {
$(el).children().each(function() {
if($(this).children().length > 0) {
reverse(this);
if($(this).justtext() != "")
reverseText(this);
} else {
reverseText(this)
}
});
}
function reverseText(el){
var text = el.textContent;
var frag = text.toString().split(/ /);
var foo = "";
var punctation_marks = [".",",","?","!"," ",":",";"];
for(i in frag){
if(punctation_marks.indexOf(frag[i]) == -1)
foo += actualReverse(frag[i],punctation_marks) + " ";
}
el.textContent = foo;
}
function actualReverse(text,punctation_marks) {
return (punctation_marks.indexOf(text.split("")[text.split("").length-1]) != -1)?text.split("").slice(0,text.split("").length-1).reverse().join("") + text.split("")[text.split("").length-1] : text.split("").reverse().join("");
}
}
编辑:使用node.nodeType并没有真正的帮助,这就是原因:
想象一下下面的HTML
<td class="gensmall">
Last visit was: Sat Mar 31, 2012 10:50 am
<br>
<a href="./search.PHP?search_id=unanswered">View unanswered posts</a> | <a href="./search.PHP?search_id=active_topics">View active topics</a>
</td>
如果我使用nodeType,只有a元素的文本会改变,而不是td本身(“last visit ….”)
解决方法:
只需找到文本节点:
var element = document.getElementById('whatever'), text = '';
for (var i = 0; i < element.childNodes.length; ++i)
if (element.childNodes[i].nodeType === 3)
text += element.childNodes[i].textContent;
编辑 – 如果你想要后代(“子”)节点中的文本,并且(现在很明显)你正在使用jQuery:
$.fn.allText = function() {
var text = '';
this.each(function() {
$(this).contents().each(function() {
if (this.nodeType == Node.TEXT_NODE)
text += this.textContent;
else if (this.nodeType == Node.ELEMENT_NODE)
text += $(this).allText();
});
});
return text;
};
坚持下去,我将测试出来:-)(似乎工作)