有4个选项卡,在这4个选项卡中有4种形式,我想编写一个jQuery程序,以便如果我在tab1中提交Form1,则应启用包含表单的tab2,而当我提交form2时,应启用包含表单3的tab3直到我到达form4.
<!DOCTYPE html>
<html lang="en">
<head>
<title>Bootstrap Case</title>
<Meta charset="utf-8">
<Meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
</head>
<body>
<div class="container">
<ul class="nav nav-tabs" id="myLinks">
<li class="active"><a data-toggle="tab" href="#home">Tab1</a></li>
<li><a href="#menu1">Tab2</a></li>
<li><a href="#menu2">Tab3</a></li>
<li><a href="#menu3">Tab4</a></li>
</ul>
<div class="tab-content" id="myTabs">
<div id="home" class="tab-pane fade in active">
<h1>Form 1</h1>
<form>
<div class="form-group">
<label for="email">Email:</label>
<input type="email" class="form-control" id="email" placeholder="Enter email">
</div>
<div class="form-group">
<label for="pwd">Password:</label>
<input type="password" class="form-control" id="pwd" placeholder="Enter password">
</div>
<div class="checkBox">
<label><input type="checkBox"> Remember me</label>
</div>
<button type="submit" class="btn btn-default">Submit</button>
</form>
</div>
<div id="menu1" class="tab-pane fade">
<h1>Form 2</h1>
<form>
<div class="form-group">
<label for="email">Email:</label>
<input type="email" class="form-control" id="email" placeholder="Enter email">
</div>
<div class="form-group">
<label for="pwd">Password:</label>
<input type="password" class="form-control" id="pwd" placeholder="Enter password">
</div>
<div class="checkBox">
<label><input type="checkBox"> Remember me</label>
</div>
<button type="submit" class="btn btn-default">Submit</button>
</form>
</div>
<div id="menu2" class="tab-pane fade">
<h1>Form 3</h1>
<form>
<div class="form-group">
<label for="email">Email:</label>
<input type="email" class="form-control" id="email" placeholder="Enter email">
</div>
<div class="form-group">
<label for="pwd">Password:</label>
<input type="password" class="form-control" id="pwd" placeholder="Enter password">
</div>
<div class="checkBox">
<label><input type="checkBox"> Remember me</label>
</div>
<button type="submit" class="btn btn-default">Submit</button>
</form>
</div>
<div id="menu3" class="tab-pane fade">
<h1>Form 4</h1>
<form>
<div class="form-group">
<label for="email">Email:</label>
<input type="email" class="form-control" id="email" placeholder="Enter email">
</div>
<div class="form-group">
<label for="pwd">Password:</label>
<input type="password" class="form-control" id="pwd" placeholder="Enter password">
</div>
<div class="checkBox">
<label><input type="checkBox"> Remember me</label>
</div>
<button type="submit" class="btn btn-default">Submit</button>
</form>
</div>
</div>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<script type="text/javascript">
$("#myTabs form").on('submit',function() {
$('#myLinks li a').each(function(){
$(this).attr('data-toggle','tab');
});
});
</script>
</body>
</html>
解决方法:
这是另一个解决方案:Working fiddle
提交表单时,需要显示下一个标签.为此,您应该标识当前li,然后为下一个li设置data-toggle =“ tab”.
$("#myTabs form").on('submit',function(e) {
e.preventDefault();
var linkHref=$(this).parents('.tab-pane').attr('id');
$('#myLinks li')
.find('a[href="#'+linkHref+'"]')
.parent()
.next()
.find('a').tab('show')
.attr('data-toggle','tab');
});