Liskov于1987年提出了一个关于继承的原则“Inheritance should ensure that any property proved about supertype objects also holds for subtype objects.”——“继承必须确保超类所拥有的性质在子类中仍然成立。”也就是说,当一个子类的实例应该能够替换任何其超类的实例时,它们之间才具有is-A关系。
public abstract class AbstractBird {
protected String color;
protected String name;
public AbstractBird(String color,String name) {
this.color = color;
this.name = name;
}
public void show() {
System.out.println("看那是" + this.name + ":颜色是" + this.color);
drinking();
goWalk();
sleep();
}
public abstract void goWalk();
public abstract void sleep();
public abstract void drinking();
}
public class Zoo {
private AbstractBird abstractBird;
public Zoo(AbstractBird abstractBird) {
this.abstractBird = abstractBird;
}
public void show() {
this.abstractBird.drinking();
}
}
public static void main(String[] args) {
// Zoo zoo = new Zoo(new Canary("红色","金丝雀"));
Zoo zoo = new Zoo(new Magpie("蓝色","喜鹊"));
// Zoo zoo = new Zoo(new Sparrow("黑色","麻雀"));
zoo.show();
对象本身有一套对自身状态进行校验的检查条件,以确保该对象的本质不发生改变,这称之为不变式(Invariant)。
public class Stone {
public Number getNumber() {
return new Integer(99);
}
}
public class Adamas extends Stone {
@Override
public Integer getNumber(){
return new Integer(22);
}
}
public class StoneClient {
public static void main(String[] args) {
Stone stone = new Adamas();
System.out.println(stone.getNumber());
}
}
答案
22
如果把父类的参数缩小,子类的参数扩大,就问题出问题
public class Stone {
public Number getNumber(HashMap map) {
return new Integer(99);
}
}
public class Adamas extends Stone {
public Number getNumber(Map map) {
return new Integer(22);
}
}
public class StoneClient {
public static void main(String[] args) {
//Stone stone = new Stone();
Adamas stone = new Adamas();
System.out.println(stone.getNumber(new HashMap()));
}
}
答案 2个打印出都是99 ,我们想要的,99,22