要求一个自然数n,我想以这种格式打印到控制台:
1 2 1 3 2 1 4 3 2 1 5 4 3 2 1 . . . n . . . 5 4 3 2 1
输入4,这是我到目前为止:
1 21 321 4321
import java.util.Scanner; public class PatternTwo { public static void main(String[] args) { Scanner in = new Scanner(system.in); int userInput; System.out.println("Please enter a number 1...9 : "); userInput = in.nextInt(); String s=""; int temp = userInput; for(int i=1; i<=userInput; i++ ) { for (int k= userInput; k>=i; k-- ) { System.out.printf(" "); } for(int j =i; j>=1; j-- ) { System.out.print(j); } System.out.println(""); } } }
解决方法
在要打印的数字前面添加一个空格,并将上面的空格加倍,使其不是金字塔.像这样的东西:
import java.util.Scanner; public class PatternTwo { public static void main(String[] args) { Scanner in = new Scanner(system.in); int userInput; System.out.println("Please enter a number 1...9 : "); userInput = in.nextInt(); String s=""; int temp = userInput; for(int i=1; i<=userInput; i++ ) { for (int k= userInput; k>i; k-- ) { // <- corrected condition System.out.printf(" "); } for(int j = i; j>=1; j-- ) { System.out.print(j); // check if not 1 to avoid a trailing space if (j != 1) { System.out.print(" "); } } System.out.println(""); } } }
编辑
感谢/u/shash678我纠正了我的解决方案,删除了所有不必要或错误的空格