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android计算地图上两点距离的算法
接口:
实现类:
接口:
package com.computedistance; public interface distanceComputeInterface { double getdistance(double lat1,double lng1,double lat2,double lng2); double getShortdistance(double lat1,double lon1,double lon2); double getLongdistance(double lat1,double lon2); double getdistanceBySpeed(double speed,double timeSpace); double getAccurancydistance(double lat_a,double lng_a,double lat_b,double lng_b); }
实现类:
package com.computedistance.impl; import java.security.InvalidParameterException; import com.baidu.mapapi.utils.distanceUtil; import com.baidu.platform.comapi.basestruct.GeoPoint; import com.computedistance.distanceComputeInterface; public class distanceComputeImpl implements distanceComputeInterface{ private final static double DEF_PI = 3.14159265359; // PI private final static double DEF_2PI= 6.28318530712; // 2*PI private final static double DEF_PI180= 0.01745329252; // PI/180.0 private final static double DEF_R =6370693.5; // radius of earth private static distanceComputeImpl instance = null; public synchronized static distanceComputeImpl getInstance(){ if (instance == null) { instance = new distanceComputeImpl(); } return instance; } private distanceComputeImpl(){} @Override public double getdistance(double lat1,double lng2) { GeoPoint p1LL = new GeoPoint((int) (lat1*1e6),(int) (lng1*1e6)); GeoPoint p2LL = new GeoPoint((int) (lat2*1e6),(int) (lng2*1e6)); double distance = distanceUtil.getdistance(p1LL,p2LL); return distance/1000; } @Override public double getShortdistance(double lat1,double lon2) { double ew1,ns1,ew2,ns2; double dx,dy,dew; double distance; // 角度转换为弧度 ew1 = lon1 * DEF_PI180; ns1 = lat1 * DEF_PI180; ew2 = lon2 * DEF_PI180; ns2 = lat2 * DEF_PI180; // 经度差 dew = ew1 - ew2; // 若跨东经和西经180 度,进行调整 if (dew > DEF_PI) dew = DEF_2PI - dew; else if (dew < -DEF_PI) dew = DEF_2PI + dew; dx = DEF_R * Math.cos(ns1) * dew; // 东西方向长度(在纬度圈上的投影长度) dy = DEF_R * (ns1 - ns2); // 南北方向长度(在经度圈上的投影长度) // 勾股定理求斜边长 distance = Math.sqrt(dx * dx + dy * dy); return distance/1000; } @Override public double getLongdistance(double lat1,ns2; double distance; // 角度转换为弧度 ew1 = lon1 * DEF_PI180; ns1 = lat1 * DEF_PI180; ew2 = lon2 * DEF_PI180; ns2 = lat2 * DEF_PI180; // 求大圆劣弧与球心所夹的角(弧度) distance = Math.sin(ns1) * Math.sin(ns2) + Math.cos(ns1) * Math.cos(ns2) * Math.cos(ew1 - ew2); // 调整到[-1..1]范围内,避免溢出 if (distance > 1.0){ distance = 1.0; } else if (distance < -1.0){ distance = -1.0; } // 求大圆劣弧长度 distance = DEF_R * Math.acos(distance); return distance/1000; } @Override public double getdistanceBySpeed(double speed,double timeSpace) { if (speed < 0 || timeSpace <= 0) { throw new InvalidParameterException(); } return speed * timeSpace; } @Override public double getAccurancydistance(double lat_a,double lng_b) { double pk = (double) (180 / 3.14169); double a1 = lat_a / pk; double a2 = lng_a / pk; double b1 = lat_b / pk; double b2 = lng_b / pk; double t1 = Math.cos(a1) * Math.cos(a2) * Math.cos(b1) * Math.cos(b2); double t2 = Math.cos(a1) * Math.sin(a2) * Math.cos(b1) * Math.sin(b2); double t3 = Math.sin(a1) * Math.sin(b1); double tt = Math.acos(t1 + t2 + t3); return 6366000 * tt / 1000; } }
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