ios – SWRevealViewController在点击前视图时关闭后视图

我正在使用SWRevealViewController来实现我的应用程序中的侧导航菜单.我想使它使得当后视图打开时,前视图不能与之互动,除非用户点击前视图,后视图将关闭,并且前视图可以再次进行交互.我有这两个SWRevealViewController委托方法,目前从前视图中删除交互.

- (void)revealController:(SWRevealViewController *)revealController willMovetoPosition:    (FrontViewPosition)position {
    if(position == FrontViewPositionLeft) {
        self.view.userInteractionEnabled = YES;
    } else {
        self.view.userInteractionEnabled = NO;
    }
}

- (void)revealController:(SWRevealViewController *)revealController didMovetoPosition:    (FrontViewPosition)position {
    if(position == FrontViewPositionLeft) {
        self.view.userInteractionEnabled = YES;
    } else {
        self.view.userInteractionEnabled = NO;
    }
}

但是,当前视图被轻拍时,这并不会导致后视图关闭.任何帮助将不胜感激,谢谢！

解决方法

如果您使用SWIFT,您可以在frontViewController中执行此操作：

override func viewDidLoad() {
    super.viewDidLoad()

    if self.revealViewController() != nil {

        self.view.addGestureRecognizer(self.revealViewController().panGestureRecognizer())
        self.view.addGestureRecognizer(self.revealViewController().tapGestureRecognizer())
    }

}

代码适用于TAP和PAN手势.