ios – 使用UITapGestureRecognizer传递参数

有什么办法可以用UITapGestureRecognizer传递参数吗？
我已经看到这回答了 Objective-c但是找不到swift的答案

test.userInteractionEnabled = true
let tapRecognizer = UITapGestureRecognizer(target: self,action: Selector("imageTapped4:"))
// Something like text.myParamater
test.addGestureRecognizer(tapRecognizer)

然后在func imageTapped4(){}下接收myParameter

解决方法

一种方法是将UITapGestureRecognizer子类化,然后设置属性,我在下面发布了一个例子.您还可以检查发件人并检查是否等于某个标签,类,字符串,e.t.c

class ViewController: UIViewController {

    @IBOutlet weak var label1: UILabel!
    @IBOutlet weak var image: UIImageView!

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view,typically from a nib.
        image.userInteractionEnabled = true;
        let tappy = MyTapGesture(target: self,action: #selector(self.tapped(_:)))
        image.addGestureRecognizer(tappy)
        tappy.title = "val"
    }

    func tapped(sender : MyTapGesture) {
        print(sender.title)
        label1.text = sender.title
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // dispose of any resources that can be recreated.
    }
}

class MyTapGesture: UITapGestureRecognizer {
    var title = String()
}

SO上有很多例子,看看,祝你好运.