ios – 来自Swift Xcode 6中的应用程序的iPhone电话

我检查并尝试过以前的答案,如何直接从应用程序拨打电话,但我不断收到错误.我刚刚在储物柜中制作了一个按钮,并将其连接到视图控制器.它不断给我“错误审查”,“分隔符,但这并不解决任何事情.我需要向AppDelegate或其他任何内容添加代码吗？我真的想知道在斯威夫特这样做的方式.

import UIKit

class ViewController: UIViewController {

    @IBAction func theCallMeButtonMethod(sender: AnyObject) {
      [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"telprompt:0123456789"]]
    }

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view,typically from a nib.
    }

    override func didReceiveMemoryWarning() {
       super.didReceiveMemoryWarning()
       // dispose of any resources that can be recreated.
    }


}

解决方法

此代码将帮助您：

let phone = "tel://982374234";
let url:NSURL = NSURL(string:phone);
UIApplication.sharedApplication().openURL(url);

要么

var url:NSURL = NSURL(string: "tel://9809088798")
UIApplication.sharedApplication().openURL(url)