我需要在JSON中构建一个简单的JSON数组,但在循环中它会在每次迭代期间覆盖第一个值.
def jsonBuilder = new groovy.json.JsonBuilder() contact.each { jsonBuilder.contact( FirstName: it.getFirstName(),LastName: it.getLastName(),Title: it.getTitle(),) }
它只返回简单的JSON并覆盖每次迭代的值并保留最后一个迭代的值.在groovy中构造JSON数组的语法是什么?
解决方法
诀窍是从联系人列表中收集.假设合同列表的结构如下,请按照下面使用jsonBuilder的方式进行操作.
def contact = [ [ getFirstName : { 'A' },getLastName : { 'B' },getTitle : { 'C' } ],[ getFirstName : { 'D' },getLastName : { 'E' },getTitle : { 'F' } ],[ getFirstName : { 'G' },getLastName : { 'H' },getTitle : { 'I' } ] ] def jsonBuilder = new groovy.json.JsonBuilder() jsonBuilder { contacts contact.collect { [ FirstName: it.getFirstName(),LastName: it.getLastName(),Title: it.getTitle() ] } } println jsonBuilder.toPrettyString() // Prints { "contacts": [ { "FirstName": "A","LastName": "B","Title": "C" },{ "FirstName": "D","LastName": "E","Title": "F" },{ "FirstName": "G","LastName": "H","Title": "I" } ] }
如果您正在寻找JSONArray而不是JSONObject作为最终结构,那么使用:
jsonBuilder( contact.collect { [ FirstName: it.getFirstName(),Title: it.getTitle() ] } ) // OP [ { "FirstName": "A","Title": "C" },{ "FirstName": "D","Title": "F" },{ "FirstName": "G","Title": "I" } ]
它没有意义,但如果结构需要如下所示
[ { "contact": { "FirstName": "A","Title": "C" } },{ "contact": { "FirstName": "D","Title": "F" } },{ "contact": { "FirstName": "G","Title": "I" } } ]
然后用
jsonBuilder( contact.collect { [ contact : [ FirstName: it.getFirstName(),Title: it.getTitle() ] ] } )