问题描述
这个:
$select = $db->select()->from(array("s" => "sles"), array("s.id","i.id as instanceid","i.reference","i.name","i.sic_code","i.start_date"))
->join(array('i' => "sle_instances"),"s.id = i.sle_id",array())
->where("i.id = (select max(id) from sle_instances where sle_id = s.id)")
->order('i.name asc');
给出以下内容:
"SELECT `s`.`id`, `i`.`id` AS `instanceid`, `i`.`reference`, `i`.`name`, `i`.`sic_code`, `i`.`start_date` FROM `sles` AS `s`
INNER JOIN `sle_instances` AS `i` ON s.id = i.sle_id WHERE (i.id = (select max(id) from sle_instances where sle_id = s.id)) ORDER BY `i`.`name` asc"
解决方法
我在将下面的SQL转换为Zend Db查询时遇到了一些问题。
$select = ' SELECT s.id,i.id as instance_id,i.reference,i.name,i.sic_code,i.start_date
FROM sles s
JOIN sle_instances i
ON s.id = i.sle_id
WHERE i.id = ( SELECT MAX(id)
FROM sle_instances
WHERE sle_id = s.id
)
ORDER BY i.name ASC';
我之前已经了解了代码-但Zend Db无法正确生成查询。谁能告诉我我想念的东西吗?
$select = $db->select() ->from('sles',array( 'id','instance_id' => 'sle_instances.id','reference' => 'sle_instances.reference','name' => 'sle_instances.name','sic_code' => 'sle_instances.sic_code','start_date' => 'sle_instances.start_date'
)
)
->join('sle_instances','sles.id = sle_instances.sle_id')
->where('sles.id = (SELECT MAX(id) FROM sle_instances WHERE sle_id = sles.id)')
->order('sle_instances.name ASC');
SQL确实可以正常工作。我想使用Zend Paginator功能来使用Zend Db重写它。
任何帮助是极大的赞赏。
J