问题描述
试试这个: a = values3[0] a = str(a).split(".")[0]
解决方法
此代码打印为 output [8.1]
。我想打印8
cursor.execute ('SELECT date FROM Archive WHERE product =?',(element,))
values3 = [row [0] for row in cursor]
#values3 is [8.1]
我用过,但我得到错误AttributeError: 'list' object has no attribute 'split'
a = values3.split('.')
b = a[0]
print(b)
你能帮我吗?谢谢