问题描述
我正在尝试解决以下问题
我有3个列表
A {1.2.3.4.5}
B {6,7}
C {8,9,10,11,12,13,14,15}
,限制为4(可配置) 那么输出应该是这样的,列表被拆分为不超过4个元素 列表元素根据其列表号(最多4个元素)放在子列表中。
以上示例的输出:
- A {1,2,3,4},B {},C {}
- A {5},B {6,7},C {8}
- A {},B {},C {9,12}
- A {},B {},C {13,15}
我尝试使用下面的代码拆分列表
我正在获取输出 [1、2、3、4] [] [] 我不能前进到下一个列表。有没有人有建议。 我知道我的编程技巧很差。请帮忙。
public void listDivider() {
ArrayList<String> al1 = new ArrayList<String>();
ArrayList<String> al2 = new ArrayList<String>();
ArrayList<String> al3 = new ArrayList<String>();
al1.add("1");
al1.add("2");
al1.add("3");
al1.add("4");
al1.add("5");
System.out.println("List 1>" + al1);
al2.add("6");
al2.add("7");
System.out.println("List 2>" + al2);
al3.add("8");
al3.add("9");
al3.add("10");
al3.add("11");
al3.add("12");
al3.add("13");
al3.add("14");
al3.add("15");
float batchSize = 4;
float totalListElements = Math.round((al1.size() + al2.size() + al3.size()) / batchSize);
LinkedList<String> allElements = new LinkedList<String>();
allElements.addAll(al1);
allElements.add("|");
allElements.addAll(al2);
allElements.add("|");
allElements.addAll(al3);
ArrayList<String> added1 = new ArrayList<>();
ArrayList<String> added2 = new ArrayList<>();
ArrayList<String> added3 = new ArrayList<>();
int position = 0;
int count = 0;
for (int i = 0; i < allElements.size(); i++) {
String check = allElements.get(i);
if (check.equals("|")) {
position++;
}
if (count <= 4) {
if (position == 1) {
if (count == 4) {
count = 0;
System.out.print(added1);
System.out.print(added2);
System.out.print(added3);
added1.clear();
added2.clear();
added3.clear();
break;
}
added1.add(allElements.removeFirst());
count++;
}
}
}
System.out.println("\n\n\n\n"+allElements);
}
解决方法
尝试一下。
static void splitBatch(int batchSize,List<String>...lists) {
int length = lists.length;
int[] indexes = new int[length];
int total = 0;
for (List<String> list : lists)
total += list.size();
int selected = 0;
List<List<String>> batch = new ArrayList<>();
while (selected < total) {
batch.clear();
int count = batchSize;
for (int i = 0; i < length; ++i) {
int index = indexes[i];
int size = lists[i].size();
int subSize = Math.min(count,Math.min(batchSize,size - index));
List<String> sublist = lists[i].subList(index,index + subSize);
batch.add(sublist);
indexes[i] += subSize;
count -= subSize;
selected += subSize;
}
System.out.println(batch);
}
}
和
List<String> a = List.of("1","2","3","4","5");
List<String> b = List.of("6","7");
List<String> c = List.of("8","9","10","11","12","13","14","15");
splitBatch(4,a,b,c);
输出
[[1,2,3,4],[],[]]
[[5],[6,7],[8]]
[[],[9,10,11,12]]
[[],[13,14,15]]
如果您有四个列表且批处理大小为6。
List<String> a = List.of("1","15");
List<String> d = List.of("16","17","18");
splitBatch(6,c,d);
输出
[[1,4,5],[6],[]]
[[],[7],[8,9,12],15],[16,17,18]]