如何在不阻止gui的情况下从Qt5 gui打开http.server？

问题描述

我使用Python 3.7和Qt5制作了一个UI。

有一个按钮可以启动本地http.server并打开一个页面以显示一些报告数据。

问题是当我单击按钮时，它运行我的脚本，启动服务器并正确打开页面，但我的用户界面被阻止。就像在ui再次工作之前等待服务器完成其工作一样。

我读到ui Tq不好用多线程。是否有任何技巧可以独立于我的用户界面打开http.server？

该方法由按钮运行时的代码：

def OpenReport():
    class ReportHTTPHandler (http.server.SimpleHTTPRequestHandler):
        def run_cgi(self,reportclass):
            # Setup environment variables -
            _,_,query = self.path.partition ('?')

            os.environ['QUERY_STRING'] = query

            # Cookies
            co = filter (None,self.headers.get_all ('cookie',[]))
            cookie_str = ','.join (co)
            if cookie_str:
                os.environ['HTTP_COOKIE'] = cookie_str

            cgitb.enable ()

            f = io.StringIO ()
            with redirect_stdout (f):
                reportclass.runCGI (self)

            output = f.getvalue ()
            self.send_response (HTTPStatus.OK,'')
            self.flush_headers ()

            self.wfile.write (''.join (output).encode ())
            self.wfile.flush ()
            return

        def send_head(self):
            # Split the query string for parsing later
            path,query = self.path.partition ('?')
            # Check if URL is a report
            # This is not the neatest way
            if path == '/cgi/index.py':
                return ReportHTTPHandler.run_cgi (self,ReportIndex)
            elif path == '/cgi/facebook.py':
                return ReportHTTPHandler.run_cgi (self,ReportFacebook)
            elif path == '/cgi/google-map.py':
                return ReportHTTPHandler.run_cgi (self,ReportGoogleMap)
            elif path == '/cgi/instagram.py':
                return ReportHTTPHandler.run_cgi (self,ReportInstagram)
            elif path == '/cgi/linkedin.py':
                return ReportHTTPHandler.run_cgi (self,ReportLinkedIn)
            elif path == '/cgi/sms.py':
                return ReportHTTPHandler.run_cgi (self,ReportSMS)
            elif path == '/cgi/telegram.py':
                return ReportHTTPHandler.run_cgi (self,ReportTelegram)
            elif path == '/cgi/twitter.py':
                return ReportHTTPHandler.run_cgi (self,ReportTwitter)
            else:
                # Assume this is an asset
                return http.server.SimpleHTTPRequestHandler.send_head (self)


    port = 50000
    address = ("",port)
    server = http.server.HTTPServer

    handler = ReportHTTPHandler

    httpd = server (address,handler)
    print (f"Report tool server started on port {port}")
    webbrowser.open (f'http://localhost:{port}/cgi/index.py',new=2)

    try:
        httpd.serve_forever ()
    except KeyboardInterrupt:
        print ("\nKeyboard interrupt received,exiting.")
        sys.exit (0)

加载ui并运行服务器的代码：

# === Load the UI =========================================
gui = QtWidgets.QApplication([])
ui = uic.loadUi('ui/MyUI.ui')
ui.button_Report.clicked.connect(OpenReport)
ui.show()
gui.exec()

解决方法

点击按钮后，您可以在线程中启动服务器，并将状态发送回用户界面

<div><div>Hello</div></div>