将Symfony services.yaml和security.yaml转换为php格式

问题描述

我想将所有配置文件从YAML转换为PHP格式。

问题

我有这个services.yaml：

services:
    # default configuration for services in *this* file
    _defaults:
        autowire: true      # Automatically injects dependencies in your services.
        autoconfigure: true # Automatically registers your services as commands,event subscribers,etc.

    # makes classes in src/ available to be used as services
    # this creates a service per class whose id is the fully-qualified class name
    App\:
        resource: '../src/*'
        exclude: '../src/{DependencyInjection,Entity,Migrations,Tests,Kernel.PHP}'

    # controllers are imported separately to make sure services can be injected
    # as action arguments even if you don't extend any base controller class
    App\Controller\:
        resource: '../src/Controller'
        tags: ['controller.service_arguments']

    App\EventListener\ExceptionListener:
        tags:
            - { name: kernel.event_listener,event: kernel.exception }

我的security.yaml

security:
    encoders:
        App\Entity\User:
            algorithm: auto
    providers:
        users:
            entity:
                class: 'App\Entity\User'
                property: 'username'

等效的services.PHP和security.PHP应该是什么？我尝试过services.PHP：

<?PHP

namespace Symfony\Component\DependencyInjection\Loader\Configurator;

use App\EventListener\ExceptionListener;

return function(ContainerConfigurator $configurator) {
    $services = $configurator->services()
        ->defaults()
        ->autowire()      // Automatically injects dependencies in your services.
        ->autoconfigure() // Automatically registers your services as commands,etc.
    ;

    // makes classes in src/ available to be used as services
    // this creates a service per class whose id is the fully-qualified class name
    $services->load('App\\','../src/*')
        ->exclude('../src/{DependencyInjection,Kernel.PHP}');

    // ?????
    // How to get $container here?
    // ?????
    $container->register(ExceptionListener::class)
        ->addTag('kernel.event_listener',['event' => 'kernel.exception'])
    ;
};

它对我不起作用...我不知道如何将$ container注入此文件

解决方法

基本问题是，需要更新在文档中注册事件侦听器的示例。像这样：

# config\services.php
return function (ContainerConfigurator $configurator) {
    $services = $configurator->services()->defaults()
        ->autowire()
        ->autoconfigure();
    ...
    $services->set(ExceptionListener::class)
        ->tag('kernel.event_listener',['event' => KernelEvents::EXCEPTION]);

脱离主题，但使用event subscriber将消除对其进行配置的需要。

就安全性配置文件而言，它只是一个很大的php数组。您从文档中的示例开始，然后只是找出密钥的问题。我认为这是一个涵盖您的问题的示例：

# config/packages/security.php

// Keeps IDE happy
/** @var ContainerBuilder $container */
$container = isset($container) ? $container : null;

$container->loadFromExtension('security',[

    'enable_authenticator_manager' => true,// 5.1 or later

    'encoders' => [
        User::class => [
            'algorithm' => 'auto','cost' => 12,]
    ],'providers' => [
        'user_provider' => [
            'entity' => [
                'class' => User::class,],'firewalls' => [
        'dev' => [
            'pattern' => '^/(_(profiler|wdt)|css|images|js)/','security' => false,'main' => [
            'lazy' => true,'provider' => 'user_provider','guard' => [
                'authenticators' => [
                    UserLoginFormAuthenticator::class,]
            ],'logout' => [
                'path'   => 'user_logout','target' => 'home_index'
            ],// Don't want to go to far down this rabbit hole
    'access_control' => [
        ['path' => '^/admin','roles' => 'ROLE_ADMIN'],//['path' => '^/home','roles' => AccessListener::PUBLIC_ACCESS],['path' => '^/user/login',]);

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