问题描述
这是我想在Laravel中进行的查询:
SELECT
product_translations.name,product_translations.description,products.ean_code
FROM product_translations,products,languages
WHERE product_translations.language_id = languages.id
AND products.id = product_translations.product_id
AND languages.language_code = "en";
Laravel中的关系
class Product extends Model
{
public function translations ()
{
return $this->hasMany(ProductTranslation::class,'product_id');
}
}
class ProductTranslation extends Model
{
public function product()
{
return $this->belongsTo(Product::class,'product_id');
}
public function language()
{
return $this->belongsTo(Language::class,'language_id');
}
}
class Language extends Model
{
public function ProductTranslations()
{
return $this->hasMany(ProductTranslation::class,'language_id');
}
}
这是正确的吗?原始查询有效。 谢谢
解决方法
您使用的查询语法是一种旧式语法,将为表生成内部联接。使用laravel,您可以使用内置方法从相关模型中查询数据。
对于您的问题,我相信您需要产品列表,但需要特定的翻译
$products = Product::with(['translations' => function($query)
{
$query->join('product_translations as pt','products.id','=','pt.cart_id')
->join('languages as l','l.id','pt.language_id')
->where('l.language_code','en')
->first();
}])->get();
或者,如果您想使用查询构建器,则可以写为
$products = DB::table('products AS p')
->select([
'p.id','p.is_organic','pt.name','pt.description','pt.ean_code'
])
->join('product_translations AS pt','pt.product_id','p.id' )
->join('languages AS l','pt.language_id','l.id')
->where('l.language_code','en')
->get();
在SQL中
SELECT
p.id,p.is_organic,pt.name,pt.description,pt.ean_code
FROM products p
INNER JOIN product_translations as pt ON pt.product_id = p.id
INNER JOIN languages l ON pt.language_id = l.id
WHERE l.language_code = "en";