是否向Discord Bot添加更多参数？

问题描述

我为我的D＆D小组写了一个基本的discord Bot。它使我们可以使用命令掷骰子并发送结果，而无需使用荣誉系统来说掷骰子。但是，它有两个主要缺点：

1：您一次只能掷一个骰子，并且

2：您不能添加任何修饰符。

我已经看到许多discord Bot，尤其是那些在YouTube上搜索音乐的Bot，它们在运行命令时可以具有多个参数，例如“！play songname ”。我该如何使我的机器人具有多个参数，例如！roll（骰子类型，数量，修饰符），而不仅仅是！roll_d20？

代码如下：

import discord
from discord.ext import commands # used to create bot commands

import random # adding this fixed a problem,don't delete
from random import randint # generates random numbers for dice rolls

import sys # used to safely shut down the bot

bot = commands.Bot(command_prefix='!') # creates an instance of a bot
    
@bot.event # says when the bot should be ready as a message in the IDE
async def on_ready():
    print("Ready to roll!")

@bot.command() # allows users to test the response of the bot from discord
async def test(ctx):
    await ctx.send('Ready to roll!'.format(ctx.author))

@bot.command() # rolls a d4 and shows the result
async def roll_d4(ctx):
    x = random.randint(1,4)
    await ctx.send((str(ctx.author) + ',you rolled a d4 and got a ' + str(x) + '!').format(ctx.author))

@bot.command() # rolls a d6 and shows the result
async def roll_d6(ctx):
    x = random.randint(1,6)
    await ctx.send((str(ctx.author) + ',you rolled a d6 got a ' + str(x) + '!').format(ctx.author))

@bot.command() # rolls a d8 and shows the result
async def roll_d8(ctx):
    x = random.randint(1,8)
    await ctx.send((str(ctx.author) + ',you rolled a d8 got a ' + str(x) + '!').format(ctx.author))

@bot.command() # rolls a d10 and shows the result
async def roll_d10(ctx):
    x = random.randint(1,10)
    await ctx.send((str(ctx.author) + ',you rolled a d10 got a ' + str(x) + '!').format(ctx.author))

@bot.command() # rolls a d12 and shows the result
async def roll_d12(ctx):
    x = random.randint(1,12)
    await ctx.send((str(ctx.author) + ',you rolled a d12 got a ' + str(x) + '!').format(ctx.author))

@bot.command() # rolls a d20 and shows the result
async def roll_d20(ctx):
    x = random.randint(1,20)
    if x == 1:
        await ctx.send((str(ctx.author) + ',you rolled a d20 and got a Nat 1!').format(ctx.author))
    elif x == 20:
        await ctx.send((str(ctx.author) + ',you rolled a d20 and got a Nat 20!').format(ctx.author))
    else:
        await ctx.send((str(ctx.author) + ',you rolled a d20 and got a ' + str(x) + '!').format(ctx.author))

@bot.command() # rolls a d100 and shows the result
async def roll_d100(ctx):
    x = random.randint(1,100)
    await ctx.send((str(ctx.author) + ',you rolled a d100 got a ' + str(x) + '!').format(ctx.author))

@bot.command() # shuts down the bot
async def stop(ctx):
    await ctx.send(("Logging out. See you next session!").format(ctx.author))
    sys.exit()

bot.run('token')

解决方法

您可以轻松地将所有命令组合为一个，如下所示，我不知道D＆D，所以我没有理解修饰符的含义。

@bot.command()
async def dice(ctx,dice_type: int,amount: int):
    results = []
    for role in range(amount):
        x = random.randint(1,dice_type)
        results.append(x)

    await ctx.send(f'You have rolled {dice_type} for {amount} times and got {results}')

您可以执行字符串操作以接收用户消息，就像/ roll'骰子数'd'有多少骰子面孔'+'修饰符'一样，我在Discord Bot上执行了一个命令来滚动任何数量的任何类型并添加修饰符。

我所做的就是获取用户消息，用空格分开，将其中带有'd'的therms放入骰子列表，将任何其他therms放入奖励列表，最后选择一个介于1和数量之间的随机数。每种骰子都有骰子面。

这里是包含我自己的Discord Bot骰子齿轮的github链接

https://github.com/Voz-bonita/Discord-Bot/blob/master/Dices%20extension.py

discord.py python