问题描述
我有以下数据:
with cte (id,[months]) as (
select 1,'July 2019' union all
select 2,'July 2019' union all
select 3,'July 2019' union all
select 4,'July 2019' union all
select 5,'August 2019' union all
select 6,'August 2019' union all
select 7,'September 2019' union all
select 8,'October 2019' union all
select 9,'November 2019' union all
select 10,'December 2019' union all
select 11,'January 2020' union all
select 12,'January 2020' union all
select 13,'January 2020' union all
select 14,'January 2020' union all
select 15,'February 2020' union all
select 16,'March 2020' union all
select 17,'March 2020' union all
select 18,'April 2020' union all
select 19,'May 2020' union all
select 20,'June 2020'
)
我需要创建一个排序列,以对所有相同的months
用相同的数字进行排名。
我使用以下代码遇到的问题是,它无法正确排序,也无法为我提供预期的结果:
select
*,dense_rank() over (partition by months order by id) Sort
from cte
当前结果:
我的预期结果:
我应该如何更改脚本以实现此目的?
解决方法
经过大量的努力,我设法使用以下脚本解决了这个问题:
select
*,convert(date,'01 '+Months) MonthsConvertedToDate,dense_rank() over (order by convert(date,'01 '+Months)) Sort
from cte
order by sort,id
结果:
参见演示here
但是我愿意提出更好的建议:-)