批处理文件从变量中未知数量的定界符中提取某些标记

问题描述

第三次，希望是最后的问题改进...

批处理文件将文本文件逐行读入for循环到变量中。所述文本文件的每一行都可以与下一行完全格式化。唯一常见的定界符是每行某处的四位数字（年份）。目的是通过回显为每行返回上述四位数字之后的任何文本。

文本文件示例：

Monday,January 1,1900 there was an event-e6718
On this day in 1904 nothing occurred
Wednesday,March 3,1908 an error occurred when attempting to access the log
Thursday,1911 - access denied
Friday,in whatever month,on whatever day,in 1938,nothing happened

因此，根据上述文本文件示例，返回结果将类似于...

there was an event-e6718
nothing occurred
an error occurred when attempting to access the log
- access denied
nothing happened

从1318 PST开始，我已经尝试了以下注释中的每个代码段，但没有一个能够返回我需要返回的数据。

但是，这些评论与我最初提出的问题有关，此问题已得到明显改善。

我什至尝试过正则表达式“ ^ [1-9] [0-9] [0-9] [0-9] $”，但是我是新手正则表达式，所以我确定我错了。

这有可能吗？

谢谢。

解决方法

批量生产是一项可怕的任务。 REGEX是一个很好的工具，但是cmd不支持它（除了findstr严重受损的子集之外）。如果您愿意使用external tool，则变得很容易：

<old.txt call jrepl ".*(\d{4})\D\ *(.*$)" "$2" >new.txt

搜索一个四位数的数字\d{4}，后跟一个非数字的\D和零个或多个空格，然后取其余的字符直到“ EndOfLine” .*$。 （括号）标记匹配，由$x引用。您所需的字符串在$2中。

输出示例文件：

there was an event-e6718
nothing occurred
an error occurred when attempting to access the log
- access denied
there was an event-dsfd318
nothing happened

如果您决定包括年份，则可以在$1中找到它：

<old.txt call jrepl ".*(\d{4})\D\ *(.*$)" "$1: $2" >new.txt

给予：

1900: there was an event-e6718
1904: nothing occurred
1908: an error occurred when attempting to access the log
1911: - access denied
1910: there was an event-dsfd318
1938: nothing happened

call是批处理文件所必需的，因为jrepl是批处理文件，因此如果没有call就不会返回。
（REGEX模式可能有待改进；我对此没有太多经验。）

jrepl.bat由dbenham编程。

,

如果字符串中确实没有公共点或令牌计数没有一致性，请在下面的for循环中调整迭代次数以匹配可能的最大令牌。

@Echo off & Setlocal EnableDelayedexpansion
  Set "event=Monday,January 1,1900 there was an event-e6718"
  For /L %%i in (1 1 10) Do (
   Set "event=!event:*,=!"
  )& rem // arbitrary number of iterations that should be adjusted to match the maximum expected tokens
  Set "event=%event:~5,100%"& rem // remove the year[space] from the string - final string maximum length is also arbitrary and may need adjusting.
  Echo/%event%

**更新** 使用上述方法的宏版本来获取for循环中最后一个令牌的宏示例：

注意：您需要调整输入文件的文件路径。

@Echo off

(Set \n=^^^
%=Newline Var=%
)

  Set Gettoken=For %%n in (1 2) Do if %%n==2 (%\n%
    For /F "Delims=" %%G in ("!string!") Do (%\n%
    Set "output=%%G"%\n%
    For %%D in ("!Delim!") Do For /L %%i in (1 1 10) Do Set "output=!output:*%%~D=!"%\n%
    Set "output=!output:~5,100!"%\n%
  )%\n%
  Set output%\n%
) Else Set string=
Setlocal EnableDelayedExpansion
 Set "Delim=,"&& For /F "Delims=" %%I in (inputfile.txt) Do %GetToken%%%I

编辑：

单批次解决方案，以解决实际问题。

@Echo off & CD "%~dp0"
Setlocal Enabledelayedexpansion
rem // replace inputfile.txt with your filepath
For /F "Delims=" %%L in (inputfile.txt) Do (
Call :sub "%%L"
rem // the below for loop will remove everything up to including the first year from the string
rem // as well as traling coma[space] / [space]
For %%E in (!Errorlevel!) Do (
 If Not "%%E"=="0" (
  Set "String=!String:*%%E=####!"
  Set "String=!String:####,=!"
  Set "String=!String:#### =!"
  Set "String=!String:####=!"
 )
)
rem // output only if a year "delimiter" was encountered
If not "%%~L"=="!String!" Echo/!String!
)

Exit /b
:sub
Set "String=%~1"
rem // adjust for loop %%I for valid year range and %%# for maximum expected string length
For /L %%I in (1899 1 2050) Do (For /L %%# in (0 1 100) Do (If "!String:~%%#,4!"=="%%I" (Exit /B %%I)))
Exit /B 0

,

尝试一下：

from selenium.webdriver.common.keys import Keys
...
driver.find_element_by_id('okta-signin-username').send_keys(USERNAME)
password_field = driver.find_element_by_id('okta-signin-password')
password_field.send_keys(PASSWORD)
password_field.send_keys(Keys.RETURN)

textfile.txt

@echo off & setlocal enabledelayedexpansion
for /f "delims=" %%i in ('type "C:\textfile.txt" ^| findstr /IRC:"there was an event"') do (
   set "event=%%i"
   echo "!event:*there was an event=there was an event!"
)

结果：