使用botkit时，请使用“ response_action”来响应view_submission

问题描述

我有一个简单的模态，其视图使用：

           const result = await bot.api.views.open({
                trigger_id: message.trigger_id,view: {
                    "type": "modal","submit": {
                        "type": "plain_text","text": "Submit","emoji": true
                    },"title": {
                        "type": "plain_text","text": "Request","blocks": [
                        {
                            "type": "input","block_id" : "accblock","element": {
                                "type": "plain_text_input","action_id": "account_name","multiline": false
                            },"label": {
                                "type": "plain_text","text": "Account Name","emoji": true
                            }
                        }
                    ]
                }
            });

如果在view_submission上输入了某个值，我需要向块添加错误。我了解我应该使用以下JSON发送响应：

       {
          response_action: 'errors',errors: {
            "ticket-desc": 'I will never accept a value,you are doomed!'
          }
        }

但是，我该如何发送？我尝试使用bot.httpBody()。是否需要将此JSON作为视图对象包括在内？任何帮助表示赞赏。

解决方法

import time import torch for i in range(100): a = torch.rand(50000,256).cuda() b = torch.rand(50000,256).cuda() t1 = time.time() val = torch.diag(a @ b.t()) t2 = time.time() val2 = torch.einsum('ij,ij->i',a,b) t3 = time.time() print(t2-t1,t3-t2,torch.allclose(val,val2)) 是您需要的方法。

确保bot.httpBody()字典的关键字与您要为其提供错误消息的元素的errors匹配。

在您的情况下，它将起作用：

block_id

您不需要bot.httpBody({ response_action: 'errors',errors: { accblock: 'Your account name is invalid or in use.' } }) 响应消息，并且确实可以完成该过程。