问题描述
transactions
表模式:
--------------------------------------
| user_id | currency | amount | date |
--------------------------------------
| 1 | eur | 500 | ... |
| 1 | gbp | 100 | ... |
| 1 | usd | 10 | ... |
| 1 | usd | 10 | ... |
| 1 | gbp | 100 | ... |
| 1 | usd | 10 | ... |
| 1 | usd | 10 | ... |
| 2 | jpy | 99 | ... |
| 1 | jpy | 99 | ... |
--------------------------------------
我想要什么:
-----------------------------------
| | total balances |
| user_id | eur | usd | gbp | jpy |
-----------------------------------
| 1 | 500 | 40 | 200 | 99 |
| 2 | 0 | 0 | 0 | 99 |
-----------------------------------
我的查询代码(使用Laravel的雄辩的ORM):
$query = DB::table('users AS u')
->join ('transactions AS t1','t1.user_id','=','u.id')
->where('t1.currency','eur')
->join ('transactions AS t2','t2.user_id','u.id')
->where('t2.currency','usd')
->join ('transactions AS t3','t3.user_id','u.id')
->where('t3.currency','gbp')
->join ('transactions AS t4','t4.user_id','u.id')
->where('t4.currency','jpy')
->selectRaw('
u.id AS u_id,u.username AS u_username,SUM(t1.amount) AS total_eur,SUM(t2.amount) AS total_usd,SUM(t3.amount) AS total_gbp,SUM(t4.amount) AS total_jpy
')
->groupBy('u.id');
dd($query->get());
产生的SQL:
select
SUM(t1.amount) AS total_eur,SUM(t2.amount) AS total_gbp,SUM(t3.amount) AS total_usd,SUM(t4.amount) AS total_jpy,u.id AS u_id,u.username AS u_username
from `users` as `u`
left join `transactions` as `t1` on `t1`.`user_id` = `u`.`id`
left join `transactions` as `t2` on `t2`.`user_id` = `u`.`id`
left join `transactions` as `t3` on `t3`.`user_id` = `u`.`id`
left join `transactions` as `t4` on `t4`.`user_id` = `u`.`id`
where `t1`.`wallet_type` = 'eur'
and `t2`.`wallet_type` = 'gbp'
and `t3`.`wallet_type` = 'usd'
and `t3`.`wallet_type` = 'jpy'
group by `u`.`id`
使用3个或更多联接(transactions
表只有约600行)时,非常慢
当我仅使用两种货币/仅使用两次联接时,速度非常快(不到1秒)
我认为多次连接同一张表是一个坏习惯。
有什么方法可以优化查询?
解决方法
您需要类似的东西
$query = DB::table('users AS u')
->join ('transactions AS t1','t1.user_id','=','u.id')
->selectRaw('
u.id AS u_id,u.username AS u_username,SUM(CASE WHEN t1.currency = \'eur\' THEN t1.amount END) AS total_eur,SUM(CASE WHEN t1.currency = \'usd\' THEN t1.amount END) AS total_usd,SUM(CASE WHEN t1.currency = \'gbp\' THEN t1.amount END) AS total_gbp,SUM(CASE WHEN t1.currency = \'jpy\' THEN t1.amount END) AS total_jpy
')
->groupBy('u.id');
检查语法-我不使用Laravel。
如果某些用户数据中未列出某种货币,则将为NULL。如果需要零,则将表达式扩展到CASE WHEN t1.currency = \'xxx\' THEN t1.amount ELSE 0 END