Coq:一元到二进制转换

问题描述

任务:编写一个将自然数转换为二进制数的函数。

Inductive bin : Type :=
  | Z
  | A (n : bin)
  | B (n : bin).

(* Division by 2. Returns (quotient,remainder) *)
Fixpoint div2_aux (n accum : nat) : (nat * nat) :=
  match n with
  | O => (accum,O)
  | S O => (accum,S O)
  | S (S n') => div2_aux n' (S accum)
  end.

Fixpoint nat_to_bin (n: nat) : bin :=
  let (q,r) := (div2_aux n 0) in
  match q,r with
  | O,O => Z
  | O,1 => B Z
  | _,O => A (nat_to_bin q)
  | _,_ => B (nat_to_bin q)
  end.

第二个函数给出错误,因为它在结构上不是递归的:

Recursive call to nat_to_bin has principal argument equal to
"q" instead of a subterm of "n".

我应该做些什么来证明它总是终止,因为q总是小于n。

解决方法

证明q(几乎总是)小于n

(* This condition is sufficient,but a "better" one is n <> 0
   That makes the actual function slightly more complicated,though *)
Theorem div2_aux_lt {n} (prf : fst (div2_aux n 0) <> 0) : fst (div2_aux n 0) < n.
(* The proof is somewhat involved...
   I did it by proving
   forall n k,n <> 0 ->
       fst (div2_aux n k) < n + k /\ fst (div2_aux (S n) k) < S n + k
   by induction on n first *)

然后在lt上进行有根据的归纳:

Require Import Arith.Wf_nat.

Definition nat_to_bin (n : nat) : bin :=
  lt_wf_rec (* Recurse down a chain of lts instead of structurally *)
    n (fun _ => bin) (* Starting from n and building a bin *)
    (fun n rec => (* At each step,we have (n : nat) and (rec : forall m,m < n -> bin) *)
      match div2_aux n 0 as qr return (fst qr <> 0 -> fst qr < n) -> _ with (* Take div2_aux_lt as an argument; within the match the (div2_aux_lt n 0) in its type is rewritten in terms of the matched variables *)
      | (O,r) => fun _ => if r then Z else B Z (* Commoning up cases for brevity *)
      | (S _ as q,r) => (* note: O is "true" and S _ is "false" *)
        fun prf => (if r then A else B) (rec q (prf ltac:(discriminate)))
      end div2_aux_lt).

我可能建议让div2_aux返回nat * bool

或者,Program Fixpoint也支持以下归纳法:

Require Import Program.

(* I don't like the automatic introing in program_simpl and
   now/easy can solve some of our obligations. *)
#[local] Obligation Tactic := (now program_simpl) + cbv zeta.
(* {measure n} is short for {measure n lt},which can replace the
   core language {struct arg} when in a Program Fixpoint
   (n can be any expression and lt can be any well-founded relation 
   on the type of that expression) *)
#[program] Fixpoint nat_to_bin (n : nat) {measure n} : bin :=
  match div2_aux n 0 with
  | (O,O) => Z
  | (O,_) => B Z
  | (q,O) => A (nat_to_bin q)
  | (q,_) => B (nat_to_bin q)
  end.
Next Obligation.
  intros n _ q [_ mem] prf%(f_equal fst).
  simpl in *.
  subst.
  apply div2_aux_lt.
  auto.
Defined.
Next Obligation.
  intros n _ q r [mem _] prf%(f_equal fst).
  specialize (mem r).
  simpl in *.
  subst.
  apply div2_aux_lt.
  auto.
Defined.

相关问答

依赖报错 idea导入项目后依赖报错,解决方案:https://blog....
错误1:代码生成器依赖和mybatis依赖冲突 启动项目时报错如下...
错误1:gradle项目控制台输出为乱码 # 解决方案:https://bl...
错误还原:在查询的过程中,传入的workType为0时,该条件不起...
报错如下,gcc版本太低 ^ server.c:5346:31: 错误:‘struct...