问题描述
我正在尝试使用Polarssl RSA库进行RSA公钥计算。我从here获得了库的源代码。尝试使用在here中定义的函数名称mpi_read_binay()时遇到问题。我对MPI结构不熟悉。我这样尝试过,
#define MAX_MPI_IN_BYTE 256
// RSA public keypair
unsigned char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
unsigned char *RSA_E = "10001";
typedef struct _key_rsa{
unsigned char *N[MAX_MPI_IN_BYTE];
unsigned char *E[MAX_MPI_IN_BYTE];
}key_rsa;
static int public_key_computation(unsigned char *inout,key_rsa key){
int j,ret = 1;
rsa_context rsa;
rsa_init(&rsa,RSA_PKCS_V15,0);
printf("public_key_computation: key.N contains\n %s\n",*key.N);
mpi_read_binary(&rsa.N,*key.N,sizeof(key.N));
printf("Inside doAll: rsa.N contains %s\n",rsa.N);
return ret ;
}
void main(){
int result,j;
result = -1;
unsigned char mes[MAX_MOD] = {1,2,3,4,5,0};
unsigned char in[MAX_MPI_IN_BYTE];
memcpy(in,mes,MAX_MPI_IN_BYTE);
key_rsa test={RSA_N,RSA_E};
result = public_key_computation(in,test);
}
输出:
public_key_computation:key.N包含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分段错误(核心已转储)
因此,问题在于每当我尝试调用该mpi_read_binary()来设置rsa.N值时,它就会崩溃。有什么帮助吗?谢谢
解决方法
暂无找到可以解决该程序问题的有效方法,小编努力寻找整理中!
如果你已经找到好的解决方法,欢迎将解决方案带上本链接一起发送给小编。
小编邮箱:dio#foxmail.com (将#修改为@)