问题描述
我正在使用sql Server 2008报表服务。我必须尝试在表达式的同一行中的不同列中拆分字符串值,但是我无法获得例外的输出。我提供了输入和输出详细信息。我必须按空格(“”)和(“-”)分割值。
输入:
示例1:
ASY-LOS,SLD,ME,A1,A5,J4A,J4B,J4O,J4P,J4S,J4T,J7,J10,J2A,J2,S2,S3,S3T,S3S,E2,E2F,E6,T6,8,SB1,E1S,OTH AS2-J4A,J1O,T8,E4,OTH
示例2:
A1 A2 A3 A5 D2 D3 D6 E2 E4 E5 E6 EOW LH LL LOS OTH P8 PH PL PZ-1,2,T1,T2,T3 R2-C,E,A RH RL S1 S2-D S3
输出应为:
谢谢。
解决方法
我写这篇文章是在报告中看到您对必须这样做的评论之前。如果您可以解释为什么无法在数据集查询中执行此操作,那么可能有解决方法。
无论如何,这是一种使用SQL的方法
DECLARE @t table (RowN int identity (1,1),sample varchar(500))
INSERT INTO @t (sample) SELECT 'ASY-LOS,SLD,ME,A1,A5,J4A,J4B,J4O,J4P,J4S,J4T,J7,J10,J2A,J2,S2,S3,S3T,S3S,E2,E2F,E6,T6,8,SB1,E1S,OTH AS2-J4A,J1O,T8,E4,OTH'
INSERT INTO @t (sample) SELECT 'A1 A2 A3 A5 D2 D3 D6 E2 E4 E5 E6 EOW LH LL LOS OTH P8 PH PL PZ-1,2,T1,T2,T3 R2-C,E,A RH RL S1 S2-D S3'
drop table if exists #s1
SELECT RowN,sample,SampleIdx = idx,SampleValue = [Value]
into #s1
from @t t
CROSS APPLY
spring..fn_Split(sample,' ') as x
drop table if exists #s2
SELECT
s1.*,s2idx = Idx,s2Value = [Value]
into #s2
FROM #s1 s1
CROSS APPLY spring..fn_Split(SampleValue,'-')
SELECT SampleKey = [1],Output = [2] FROM #s2
PIVOT (
MAX(s2Value)
FOR s2Idx IN ([1],[2])
) p
这产生了以下结果
如果您没有拆分功能,请使用以下脚本创建我使用的脚本
CREATE FUNCTION [dbo].[fn_Split]
/* Define I/O parameters WARNING! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE! */
(@pString VARCHAR(8000),@pDelimiter CHAR(1)
)
RETURNS TABLE
WITH SCHEMABINDING
AS
RETURN
/*"Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000: enough to cover VARCHAR(8000)*/
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
)--10E+1 or 10 rows,E2(N) AS (SELECT 1 FROM E1 a,E1 b)--10E+2 or 100 rows,E4(N) AS (SELECT 1 FROM E2 a,E2 b)--10E+4 or 10,000 rows max
/* This provides the "base" CTE and limits the number of rows right up front
for both a performance gain and prevention of accidental "overruns" */,cteTally(N) AS (
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
FROM E4
)
/* This returns N+1 (starting position of each "element" just once for each delimiter) */,cteStart(N1) AS (
SELECT 1 UNION ALL
SELECT t.N + 1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
)
/* Return start and length (for use in SUBSTRING later) */,cteLen(N1,L1) AS (
SELECT s.N1,ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0) - s.N1,8000)
FROM cteStart s
)
/* Do the actual split.
The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found. */
SELECT
idx = ROW_NUMBER() OVER (ORDER BY l.N1),value = SUBSTRING(@pString,l.N1,l.L1)
FROM cteLen l