使用python创建的Windows Service无法启动

问题描述

使用python（3.7）脚本创建Windows服务

import servicemanager
import socket
import sys
import win32event
import win32service
import win32serviceutil

logfile = 'service.log'
logging.basicConfig(filename=logfile,filemode='w',format='%(asctime)s - %(message)s',datefmt='%d-%b-%y %H:%M:%S',level=logging.DEBUG)


class TestService(win32serviceutil.ServiceFramework):
    _svc_name_ = "WindowService"
    _svc_display_name_ = "Test Service"
    _svc_description_ = "Test Service"

    def __init__(self,args):
        win32serviceutil.ServiceFramework.__init__(self,args)
        self.hWaitStop = win32event.CreateEvent(None,None)
        socket.setdefaulttimeout(60)

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)

    def SvcDoRun(self):
        rc = None
        while rc != win32event.WAIT_OBJECT_0:
            msg = "Service is running"
            logging.info(msg)
            rc = win32event.WaitForSingleObject(self.hWaitStop,5000)


if __name__ == '__main__':
    if len(sys.argv) == 1:
        servicemanager.Initialize()
        servicemanager.PrepareToHostSingle(TestService)
        servicemanager.StartServiceCtrlDispatcher()
    else:
        win32serviceutil.HandleCommandLine(TestService)

使用pyinstaller -F --hidden-import = win32timezone WindowsService.py

为上述脚本创建了一个exe。

使用WindowsService.exe安装并已成功安装服务 但是当我启动该服务时，我遇到了错误

windows could not start the service on local computer
Error 1053: The service did not respond to the start or control request in a timely fashion.

解决方法

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