货物运输系统的环路问题

问题描述

enter image description here 这包含了问题的所有细节

我们如何打印选项数量 我们使用这个公式options = (cargo / lorrysize) + 1这给了我们很多选择 但是之后我们陷入困境 示例货物尺寸为100

100     100/30=3+1=4
option 1
30
30
30
option 2
30
30
10
10
10
option 3
10x10
option 4
30
10x7

第二个例子

150      150/30=5+1=6
option 1
30x5
option 2
30x4
10x3
option 3
30x3
10x6
option 4
30x2
10x9
option 5
30
10x12
option 6
10x15

我们尝试这样做，但是不知道如何编写“ for循环”部分的代码 我希望这足以让你们理解

#include <iostream>
#include <vector>
#include <iterator>
#include <fstream>
#include<string>
using namespace std;

/*
Steps to complete program
Step 1: Find total options available (how many Lorrys & Vans) for the input cargo capacity in .txt files
Step 2: For each option,find its:   Amount of Lorrys and Vans
                                     Total cost for both the Lorrys and Vans
                                     Find the max trip
Step 3: Find the top 3 cheapest/lowest cost trips and display
Step 4: Find the fastest available trip and display
*/

class CTS //cargo transport system
{
int i;
    int cargo,lorryprice,vanprice,lorrysize,vansize,allOps;
    //vector<double> options,lorry,vans,totalC,nooftrips;
    //vector <double>::iterator option,minilorry,cost,trips,van;

public:
    void set_cargo(int);
    void set_lorryprice(int);
    void set_vanprice(int);
    void set_lorrysize(int);
    void set_vansize(int);

};
void CTS::set_cargo(int total_cargo){
    cargo = total_cargo;
}
void CTS::set_lorryprice(int lorryP){
    lorryprice = lorryP; 
}

void CTS::set_vanprice(int vanP){
    vanprice = vanP;
}
void CTS::set_lorrysize(int lorryS){
    lorrysize = lorryS;
}
void CTS::set_vansize(int vanS)
{
    vansize = vanS;
}

int main()
{
    int cargo,options,i;
    ifstream infile;
    infile.open("size.txt");
    if(infile.is_open()){
        infile >> cargo;
        infile >> lorryprice;
        infile >> vanprice;
        infile >> lorrysize;
        infile >> vansize;
    }
 CTS run;
    run.set_cargo(cargo);
    run.set_lorryprice(lorryprice);
    run.set_vanprice(vanprice);
    run.set_lorrysize(lorrysize);
    run.set_vansize(vansize);

    infile.close();

    options = (cargo / lorrysize) + 1;
    
    
    for (i = 0; i < options; i++)
    {
       

        cout << i << " " << cargo - lorrysize << endl; // this part we need help with we have no clue




    }
    


    /*cout << cargo << endl;
    cout << lorryprice << endl;
    cout << vanprice << endl;
    cout << lorrysize << endl;
    cout << vansize << endl;*/
    return 0;
}

解决方法

一旦您拥有最多的货车数量，您可以减去货车的货物并计算剩余的货车数量，如下所示：

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