问题描述
下面的代码在下面工作,但是我试图添加一个参数,以将SaveAsFile方法上的文件名更改为(a)我所在的消息的迭代。
例如,当前输出为
Returned mail see transcript for details
Returned mail see transcript for details
所需的输出是
Returned mail see transcript for details1
Returned mail see transcript for details2
Returned mail see transcript for details3
当前此代码仅覆盖文件夹中的相同保存文件,但是我需要完成将同一文件从不同的消息保存到新文件名。
以下代码:
import win32com.client
import os
outlook = win32com.client.dispatch("outlook.application").GetNamespace("MAPI")
inBox = outlook.GetDefaultFolder(6) # "6" refers to the index of a folder - in this case the inBox. You can change that number to reference
messages = inBox.Items
message = messages.GetFirst()
subject = message.Subject
i = 0
#
get_path = r'S:\Corporate Shared\Contracting Shared\DATA_PROJECTS\James\Email Extraction\Undeliverable Items'
for m in messages:
i = i + 1 #numeration
a = str(i) #Creates i as a string
if m.Subject == ("Returned mail: see transcript for details"):
#print(message)
attachments = message.Attachments
num_attach = len([x for x in attachments])
for x in range(1,num_attach + 1):
attachment = attachments.Item(x)
attachment.SaveASFile(os.path.join(get_path,attachment.FileName))
print(attachment)
#print(a)
message = messages.GetNext()
else:
message = messages.GetNext()
解决方法
不是在对attachment.FileName
的调用中使用os.path.join
,而是将attachment.FileName
存储在变量中,然后用"."
替换最后一个"_" + x + "."