问题描述
我有这样的ACCOUNTS表
subscr_id,txn_type,PAYMENT_START
A,signup,1
A,pay,2
A,3
A,cancel,4
B,1
B,2
B,3
我想输出A,4
和B,3
,(每个唯一的subscr_id仅按时间(PAYMENT_START)排序的最后一个值)
SELECT disTINCT subscr_id,LAST_VALUE(txn_type) OVER (
PARTITION BY subscr_id ORDER BY PAYMENT_START asc
RANGE BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING
) AS last FROM ACCOUNTS;
当我要执行此操作时,出现错误:
解决方法
假设没有为给定的订户重复payment_start
,则可以使用相关的子查询来执行所需的操作:
select a.*
from accounta a
where a.payment_start = (select max(a2.payment_start)
from accounts a2
where a2.subscr_id = a.subscr_id
)