如何获取连续元素数组对象的重复键值的计数？

编程问答 2022-12-06

问题描述

我有一个数组结构：-

 var location = [ {
  "latitude" : 21.112,"longitude" : 79.07,"time" : "8:13AM","time1" : "8:13AM"
},{
  "latitude" : 21.111,"time" : "8:20AM","time1" : "8:20AM"
},"time" : "8:34AM","time1" : "8:34AM"
},"time" : "8:41AM","time1" : "8:41AM"
},{
  "latitude" : 21.109,"time" : "8:48AM","time1" : "8:48AM"
},{
  "latitude" : 21.108,"time" : "8:55AM","time1" : "8:55AM"
},"longitude" : 79.069,"time" : "9:02AM","time1" : "9:02AM"
},{
  "latitude" : 21.107,"time" : "9:09AM","time1" : "9:09AM"
},{
  "latitude" : 21.106,"time" : "9:16AM","time1" : "9:16AM"
},{
  "latitude" : 21.105,"time" : "9:23AM","time1" : "9:23AM"
},{
  "latitude" : 21.104,"time" : "9:30AM","time1" : "9:30AM"
},"time" : "9:37AM","time1" : "9:37AM"
},"time" : "9:44AM","time1" : "9:44AM"
},"longitude" : 79.071,"time" : "9:51AM","time1" : "9:51AM"
},"longitude" : 79.072,"time" : "9:58AM","time1" : "9:58AM"
}]

我想要不算。每个对象的经度和纬度时间相同。它应该仅使用附加的count键返回数组。 例如-预期结果 

var location = [ {
  "latitude" : 21.112,"time1" : "8:13AM","count":1
},"time1" : "8:20AM","count":3
},"time1" : "8:34AM","time1" : "8:41AM",..]

我已经尝试过此代码-

const resultarray = Object.values(location.reduce((a,b) => {
  a[b.latitude + b.longitude] = Object.assign(b,{count: (a[b.latitude + b.longitude] || {count: 0}).count + 1});
  return a;
},{}));

console.log(resultarray)

但是这将返回带有count的元素的唯一对象。我希望每个对象都具有键计数。

解决方法

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