我想将我的数组值与php表中的列值进行匹配

问题描述

date_default_timezone_set('Asia/Kolkata');
header('Access-Control-Allow-Origin: *');

include_once('conn.PHP');
$data2 = array();

$content = trim(file_get_contents("PHP://input"));
$data = json_decode($content);
$couplenumber = $data->contact_number;

$sql = "SELECT * from `users_table`  where `phone`  IN  '$couplenumber'";

$result = $conn->query($sql);
if ($result->num_rows > 0) {

    while ($row = $result->fetch_assoc()) {
        array_push($data2,$row);
    }
    echo json_encode($data2);
} else {
    echo 0;
}

$conn->close();

$couplenumber是一个包含多个联系电话的数组。我想将数组值匹配到名为phone的表列。电话的字符串值表示单个联系人。将电话值匹配到多个$couplenumber值的联系人后如何获取数据？

解决方法

如果您向我们展示数组内容，那就更好了。但是，如果您有一些东西，例如一个对象数组和一个仅带有id的数组，让我们尝试一下：

//Arrays are like :
$tab1 = [3,4];
//Considering Object is a class which receive id in constrictor and has et getId method.
$obj1 = new Object(1);
$obj2 = new Object(2);
$items = [$obj1,$obj2];

$tab2 = [];
foreach ($items as $item) {
    $tab2[] = $item->getId();
}

$diff = array_merge(array_diff($tab1,$tab2),array_diff($tab2,$tab1));

// True there are same,false there differents.
var_dump( empty($diff) && (count($tab1) === count($tab2)) );

mysql select select