问题描述
我有一个(size,1)
形状的张量,我想通过移动其值将其转换为(size,lookback,1)
形状。对应的大熊猫低于
size = 7
lookback = 3
data = pd.DataFrame(np.arange(size),columns=['out']) # input
y = np.full((len(data),1),np.nan) # required/output
for j in range(lookback):
y[:,j,0] = data['out'].shift(lookback - j - 1).fillna(method="bfill")
如何在pytorch中实现类似效果?
示例输入:
[0,1,2,3,4,5,6]
所需的输出:
[[0. 0. 0.]
[0. 0. 1.]
[0. 1. 2.]
[1. 2. 3.]
[2. 3. 4.]
[3. 4. 5.]
[4. 5. 6.]]
解决方法
您可以为此使用Tensor.unfold
。首先,尽管您将需要张紧张量的前端,但是您可以使用nn.functional.pad
。例如
import torch
import torch.nn.functional as F
size = 7
loopback = 3
data = torch.arange(size,dtype=torch.float)
# pad front of data with 2 values
# replicate padding requires 3d,4d,or 5d tensor,hence the creation of two unitary dimensions before padding
data_padded = F.pad(data[None,None,...],(loopback - 1,0),'replicate')[0,...]
# unfold with window size of 3 with step size of 1
y = data_padded.unfold(dimension=0,size=loopback,step=1)
输出为
tensor([[0.,0.,0.],[0.,1.],1.,2.],[1.,2.,3.],[2.,3.,4.],[3.,4.,5.],[4.,5.,6.]])