问题描述
每当我运行此代码(C)时,程序就会跳过 scanf(“%c”,运算符)。我只是在学习C,并且感到困惑。当我在请求任何其他输入之前要求scanf(“%c”,operator)时,程序正在按预期方式工作。这里在玩什么?
#include <stdio.h>
#include <string.h>
int main() {
char variable[2];
char operator;
int first,second;
printf("Enter the variable: \n");
scanf("%s",&variable);
printf("Enter an operator (+,-): ");
scanf("%c",&operator);
printf("Enter two operands (one before equal and one after equal sign): ");
scanf("%d %d",&first,&second);
switch (operator) {
case '+':
printf("x = %d and x = %d",first + second,first - second);
break;
case '-':
printf("x = %d and x = %d",first - second);
break;
// Absolute Value for simple calculations
default:
printf("Error! Difficult computation");
}
return 0;
}
解决方法
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