如果列表中有小写元素而未将列表更改为小写

问题描述

我正在尝试创建一个程序，用字典中与之对应的单词替换输入中输入的任何单词。这是字典：

slang = {'phone': 'dog and bone','queen': 'baked bean','suit': 'whistle and flute','money': 'bees and honey','dead': 'brown bread','mate': 'china plate','shoes': 'dinky doos','telly': 'custard and jelly','boots': 'daisy roots','road': 'frog and toad','head': 'loaf of bread','soup': 'loop the loop','walk': 'ball and chalk','fork': 'roast pork','goal': 'sausage roll','stairs': 'apples and pears','face': 'boat race'} 

这是输出示例。

Sentence: I called the Queen on the phone
I called the baked bean on the dog and bone

我已经尝试编写该程序的代码，并且得到了它的输出结果（几乎）。我只是不知道如何问输入的单词是否在字典中，而不用小写字母替换大写的单词。

这是我的输出示例：

Sentence: I called the Queen on the phone
i called the baked bean on the dog and bone

这是我尝试的代码，我意识到这个问题的出现是因为我在开始时将句子设置为较低。在进入for循环之前，我曾尝试将'word'设置为较低，但这无法正常工作，因为直到for循环之前'word'都是未知的。

slang = {'phone': 'dog and bone','face': 'boat race'}
new_sentence = []
sentence = input("Sentence: ").lower()
words_list = sentence.split()
for word in words_list:
  if word in slang:
    replace = slang[word]
    new_sentence.append(replace.lower())
  if word not in slang:
    new_sentence.append(word)
separator = " "
print(separator.join(new_sentence))

非常感谢您！

解决方法

您可以改用list comprehension

slang = {'phone': 'dog and bone','queen': 'baked bean',...}

Sentence = "I called the baked bean on the dog and bone"
print(" ".join(slang.get(x.lower(),x) for x in Sentence.split()))

---

I called the baked bean on the dog and bone

,

类似以下内容：

slang = {'phone': 'dog and bone','queen': 'baked bean'}

def replace_with_slang(sentence):
  words = sentence.split(' ')
  temp = []
  for word in words:
    temp.append(slang.get(word,word))
  return ' '.join(temp)


print(replace_with_slang('I called the phone  It was the queen '))