用'+'分割字符串并搜索表中的所有行是否都存在

问题描述

我有一个表格规则，其中有2列：

1. RID
2. RuleValue

DECLARE @RuleType VARCHAR(MAX)= 'DDDD+FFFF' ;

我想在'DDDD+FFFF'列中拆分并搜索上述变量rulevalue。

下面的图像是规则表：

在rulevalue列中进行拆分和搜索之后，输出应如下所示：

解决方法

如果顺序无关紧要，则可以从变量中创建条件，然后将其与like子句中的where过滤器一起使用：

declare @Rules  table (RID int,RuleValue varchar(50))

insert into @Rules
values 
 (1,'DDDD+FFFF'),(2,'DDDD+EEEE+FFFF'),(3,'BBBB+CCCC'),(4,'BBBB+DDDD'),(5,'CCCC+EEEE'),(6,'BBBB+DDDD')

DECLARE @RuleType VARCHAR(MAX)= 'DDDD+FFFF' ;

select *
from @Rules
where RuleValue like '%' + replace(@RuleType,'+','%') + '%'

结果：

---

根据OP的评论进行编辑

如果顺序很重要，那么解决方案会比较棘手。

declare @Rules table (RID int,'BBBB+DDDD')

DECLARE @RuleType VARCHAR(MAX)=  'DDDD+FFFF+EEEE' ;

--define a table variable to hold every component of the rule type
declare @splittedRules table (SplittedRule nvarchar(max))

--fill the table variable with each component of the rule type
--since you use SQL Server 2012 you must use xml syntax to split the string
insert into @splittedRules
SELECT Split.a.value('.','NVARCHAR(MAX)') as SplittedRule
FROM
(
    SELECT CAST('<X>'+REPLACE(@RuleType,'</X><X>')+'</X>' AS XML) AS String
) AS A
CROSS APPLY String.nodes('/X') AS Split(a)

--now you can see if each rule matches a single component of the rule type
;with compare as 
(
    select 
        r.RID,r.RuleValue,spl.SplittedRule,case when CHARINDEX(spl.SplittedRule,r.RuleValue) > 0 then 1 else 0 end as ok 
    from 
        @Rules as r 
            cross apply 
        @splittedRules spl
)
--finally you can perform a group by checking 
--which rule matches all the components of the rule type
select
    RID,RuleValue   
from 
    compare
group by 
    RID,RuleValue
having 
    sum (ok)=(select count(*) from @splittedRules)
order by RID

结果：