将表格中的数据格式化为百分比

问题描述

我有一个看起来像这样的数据框：

以下是创建此DF的代码：

structure(list(ethnicity = structure(c(1L,2L,3L,5L),.Label = c("AS","BL","HI","Others","WH","Total"),class = "factor"),`Strongly agree` = c(30.7,26.2,37.4,31.6),Agree = c(43.9,34.5,41,45.4),`Neither agree nor disagree` = c(9.4,14.3,8.6,8.7),disagree = c(10,15.5,9.9,9.7),`Strongly disagree` = c(6,9.5,3.2,4.6)),row.names = c(NA,-4L),class = "data.frame")

我想添加数据条并将这些数字设置为百分比。我尝试使用formattable库来做到这一点（请参见下面的代码）。

formattable(df,align=c("l","l","l"),list(`ethnicity` = formatter("span",style = ~ style(color = "grey",font.weight = "bold")),area(col = 2:6) ~ function(x) percent(x / 100,digits = 0),area(col = 2:6) ~ color_bar("#DeF7E9")))

我面临2个问题：

1. 数字不会在表格输出中显示为百分比。
2. 对齐方式似乎在最后一列即

如果有人能帮助我了解我在这里想念的是什么，我将不胜感激？

解决方法

这是一个解决方案，但需要大量输入，我想可以使用mutate_at()，但是我只是无法找到如何在percent()部分中传递列名。使用.会产生错误。

这适用于很多输入：

library(dplyr)
library(formattable)

df %>% 
  mutate(`Strongly agree` = color_bar("#DeF7E9")(formattable::percent(`Strongly agree`/100))) %>% 
  mutate(`Agree` = color_bar("#DeF7E9")(formattable::percent(`Agree`/100))) %>% 
  mutate(`Disagree` = color_bar("#DeF7E9")(formattable::percent(`Disagree`/100))) %>%
  mutate(`Neither agree nor disagree` = color_bar("#DeF7E9")(formattable::percent(`Neither agree nor disagree`/100))) %>%
  mutate(`Strongly disagree` = color_bar("#DeF7E9")(formattable::percent(`Strongly disagree`/100))) %>%
  formattable(.,align=c("l","l","l"),`ethnicity` = formatter("span",style = ~ style(color = "grey",font.weight = "bold")))

这不起作用，但可能会得到改善：

df %>% 
  mutate_at(.vars = 2:6,.funs = color_bar("#DeF7E9")(formattable::percent(./100))) %>% 
  formattable(...)

Some more informations about this "strange" structure var = color_bar(...)(var)