问题描述
我正在学习面向对象的东西，并尝试将嵌套函数合并到我的代码中，以便我可以了解这些不同的操作如何进行工作，特别是嵌套函数。 我想将值从一个函数传递到另一个函数，然后根据每个嵌套函数的计算结果，输出某些最终数字。我无法理解如何在方法内部获取和重新声明返回值，以便可以再次使用它们。
粗单嵌套示例：
func increaseNumbers(numOne: Double,numTwo: Double) -> (Double,Double) {
var numOneIncreased = numOne + 2
var numTwoIncreased = numTwo + 5
func playWithNumbersMore(warpOne: Double,warpTwo: Double) -> (Double,Double) {
if warpOne < 50 {
var adjustedOne = warpOne + 16.5
var adjustedTwo = warpTwo + 20.8
} else { do nothing... }
return (adjustedOne,adjustedTwo)
}
playWithNumbersMore(warpOne: numOneIncreased,warpTwo: numTwoIncreased)
// How do i re-assign the return values inside playWithNumbersMore?
return (something,somethingTwo)
}
如果可以的话，这是我想做的：
func increaseNumbers(numOne: Double,adjustedTwo)
}
// I want to be able to take return values and do more with them... as well as redefine them
// on completion of final "parent function"
// Sort of like this:
var newNumbToPlayOne = adjustedOne
var newNumbToPlayTwo = adjustedTwo
func playMoreWithNewNumbers...
}
这可能吗？还是我偏离正常轨道？
解决方法
func increaseNumbers(numOne: Double,numTwo: Double) -> (Double,Double) {
var numOneIncreased = numOne + 2
var numTwoIncreased = numTwo + 5
func playWithNumbersMore(warpOne: Double,warpTwo: Double) -> (Double,Double) {
if warpOne < 50 {
var adjustedOne = warpOne + 16.5
var adjustedTwo = warpTwo + 20.8
return (adjustedOne,adjustedTwo)
}
let result = playWithNumbersMore(warpOne: numOneIncreased,warpTwo: numTwoIncreased)
numOneIncreased = result.0 // result.0 is a adjustedOne
numTwoIncreased = result.1 // result.1 is a adjustedTwo
return result
}
这是如何使用playWithNumbersMore数据的结果。 我错了吗？或者这是寻找的东西吗？