Moodle可配置报告MySQL

问题描述

我想获得一个包含用户名和用户群组以及网站上scorm活动状态的报告。我找到了两个sql 代码段，但不幸的是，我不知道如何将它们组合起来以实现所需的代码。如果有人能够帮助我，我将非常感激。

用户和同类群组

     SELECT u.firstname,u.lastname,h.idnumber,h.name
     FROM prefix_cohort AS h
     JOIN prefix_cohort_members AS hm ON h.id = hm.cohortid
     JOIN prefix_user AS u ON hm.userid = u.id
     ORDER BY u.firstname

具有严重状态的用户列表：

 SELECT
 u.username AS 'User',c.shortname AS 'Course',m.name AS Activitytype,CASE
 WHEN cm.module = 1 THEN (SELECT a1.name FROM prefix_assign a1            WHERE a1.id = cm.instance)
 WHEN cm.module = 2 THEN (SELECT a2.name FROM prefix_assignment a2    WHERE a2.id = cm.instance)
 WHEN cm.module = 3 THEN (SELECT a3.name FROM prefix_book a3               WHERE a3.id = cm.instance)
 WHEN cm.module = 4 THEN (SELECT a4.name FROM prefix_chat a4                WHERE a4.id = cm.instance)
     WHEN cm.module = 5 THEN (SELECT a5.name FROM prefix_choice a5            WHERE a5.id = cm.instance)
     WHEN cm.module = 6 THEN (SELECT a6.name FROM prefix_data a6                WHERE a6.id = cm.instance)
     WHEN cm.module = 7 THEN (SELECT a7.name FROM prefix_Feedback a7        WHERE a7.id = cm.instance)
     WHEN cm.module = 8 THEN (SELECT a8.name FROM prefix_folder a8              WHERE a8.id = cm.instance)
     WHEN cm.module = 9 THEN (SELECT a9.name FROM prefix_forum a9              WHERE a9.id = cm.instance)
     WHEN cm.module = 10 THEN (SELECT a10.name FROM prefix_glossary a10         WHERE a10.id = cm.instance)
     WHEN cm.module = 11 THEN (SELECT a11.name FROM prefix_imscp  a11           WHERE a11.id = cm.instance)
     WHEN cm.module = 12 THEN (SELECT a12.name FROM prefix_label a12              WHERE a12.id = cm.instance)
     WHEN cm.module = 13 THEN (SELECT a13.name FROM prefix_lesson a13            WHERE a13.id = cm.instance)
     WHEN cm.module = 14 THEN (SELECT a14.name FROM prefix_lti a14                    WHERE a14.id = cm.instance)
     WHEN cm.module = 15 THEN (SELECT a15.name FROM prefix_page a15               WHERE a15.id = cm.instance)
     WHEN cm.module = 16 THEN (SELECT a16.name FROM prefix_quiz  a16               WHERE a16.id = cm.instance)
     WHEN cm.module = 17 THEN (SELECT a17.name FROM prefix_resource a17         WHERE a17.id = cm.instance)
     WHEN cm.module = 18 THEN (SELECT a18.name FROM prefix_scorm a18             WHERE a18.id = cm.instance)
     WHEN cm.module = 19 THEN (SELECT a19.name FROM prefix_survey a19             WHERE a19.id = cm.instance)
     WHEN cm.module = 20 THEN (SELECT a20.name FROM prefix_url a20                      WHERE a20.id = cm.instance)
     WHEN cm.module = 21 THEN (SELECT a21.name FROM prefix_wiki a21                    WHERE a21.id = cm.instance)
     WHEN cm.module = 22 THEN (SELECT a22.name FROM prefix_workshop a22           WHERE a22.id = cm.instance)
 END AS Actvityname,# cm.section AS Coursesection,CASE
     WHEN cm.completion = 0 THEN '0 None'
     WHEN cm.completion = 1 THEN '1 Self'
     WHEN cm.completion = 2 THEN '2 Auto'
 END AS Activtycompletiontype,CASE
    WHEN cmc.completionstate = 0 THEN 'In Progress'
    WHEN cmc.completionstate = 1 THEN 'Completed'
    WHEN cmc.completionstate = 2 THEN 'Completed with Pass'
    WHEN cmc.completionstate = 3 THEN 'Completed with Fail'
    ELSE 'UnkNown'
 END AS 'Progress',DATE_FORMAT(FROM_UNIXTIME(cmc.timemodified),'%Y-%m-%d %H:%i') AS 'When'
 FROM prefix_course_modules_completion cmc
 JOIN prefix_user u ON cmc.userid = u.id
 JOIN prefix_course_modules cm ON cmc.coursemoduleid = cm.id
 JOIN prefix_course c ON cm.course = c.id
 JOIN prefix_modules m ON cm.module = m.id
 # skip the predefined admin AND guest USER
 WHERE u.id > 2
 # config reports filters
 %%FILTER_USERS:u.username%%
 %%FILTER_SEARCHTEXT:m.name:~%%
 %%FILTER_STARTTIME:cmc.timemodified:>%% %%FILTER_ENDTIME:cmc.timemodified:<%%
  
 ORDER BY u.username

解决方法

industry

moodle mysql report